Figure 3 shows the vector diagram for the three forces acting on each ball in equilibrium. They are; the tension T in the nylon string, the weight Fw of the pith balls and the Coulomb force Fc between the pith balls. The mass m on the pith balls is given above. L is the length of the nylon string. 1. From the geometry of Figure 3 if each pith ball has a mass m and the two hang from strings of length L separated by distance r because of their charge, then the charge q on each ball is given by

Two electrostatic point charges of +30 uC and +20 uC exert a repulsive force on each other of 225 N. What is the distance between the two charges.

A metallic plate holds a charge of Q = -18 nC. Does the plate have excess or lack of electrons? Excess What total number of elementary charges does Q represent? Units no units required The number of elementary charges, N = 1.125E11 After 43.1 × 10¹0 electrons were added to the plate, what is the new net charge on the pla The new charge of the plate, Qnew = Units nC

Bead A has a mass of 15 g and a charge of -5.2 nC . Bead B has a mass of 22 g and a charge of -11.7 nC . The beads are held 15 cm apart (measured between their centers) and released.

A sphere has an excess of 3 electrons. What is the charge of the sphere?    A. – 5.3 × 10^-20 C B. – 4.8 × 10^-19 C C. 5.3 × 10^-20 C D. 4.8 × 10^-20 C

If you touch 62 nC and -11 nC charges, what will be the net charge after touching them together?

Two charges +2 µC and +8 µC are placed along the z axis, with the first charge at the origin (z =0) and the second charge at z = +1 m. Find the magnitude and direction of the net force on a -2 nC charge when placed at the following locations below. Overall Hint Review Section 5.3 Coulomb's Law. Use Coulomb's Law to calculate force due to each of two charges and add them together for the net force, minding the directions. For part (c), you will need to do the vector sum (more below). a. halfway between the two charges: magnitude of force is direction is Select an answer b. on the axis at x = -0.5 m: magnitude of force is is Select an answer c. at the coordinate (x, y) = (1 m, 0.5 m) (half a meter above the +8 µC charge in a direction perpendicular to the line joining the two fixed charges): Hint for (c) This problem is fully 2-dimensional. The charge at x = 1 m exerts force along y direction; the charge at the origin exerts force along the line connecting (x, y) = (0,0) and (z,y) = (1…

The figure below shows four small beads, each with a positive charge, at the corners of a square. The length of each side of the square is a. The bead at top-right has a charge of q; the one at lower-left has a charge of 8.0q; the other two each have a charge of 6.0g. (Assume that the +x-axis is to the right and the +y-axis is up along the page.) a 6.09 а 8.0g 6.0g a (a) What is the magnitude of the force on the bead with charge q? Express your answer in terms of k, q, and a in symbolic form. ka [12.485] F = a? What is the magnitude of the force due to each charge? (Be careful with distances.) What is the direction of each force? Using trigonometry, can you find the x- and y-components of each force? After finding the x- and y-components of the net force, how can you use them to find the magnitude of the net force? (b) What is the direction of the force on the bead with charge q? (Enter your answer in degrees counterclockwise from the +x-axis.) 45 ° counterclockwise from the +x-axis

A +30 nC charge is placed at a distance r = 5 mm from a +10 nC charge in free space. Calculate the magnitude of the force between the charges. Note: ε0=8.85x10-12 Fm-1

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