Considering electron and proton as two charged particles separated by d = 4.2 x 10-¹1 m calculate the Coulomb force between proton and electron. 1 Take the electron charge-1.6 x 10-19 Cand =9x10⁹ m/F. Give the answer in nano-Newtons (nN, 10-⁹ N). Απερ Answer: Choose...

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In what way or ways would the physical universe be different if protons were negatively charged and electrons were positively charged? Gravity would be a repulsive force instead of an attractive one. Since protons are more massive, the universe would acquire a net negative charge. The value of the Coulomb constant k would change. Like charges would attract, and opposite charges would repel. Atoms would consist of protons orbiting a nucleus composed of electrons and neutrons. There would be no difference other than the sign on the charged particles.

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Atoms have an equal number of electrons and protons so are electrically neutral. Atoms that have a net electrical charge are known as "ions". Positive ions - have "missing" electrons Negative ions - have "excess" electrons 3. The net charge of an object can be found be summing the individual charges. Since charge is quantized, all net charges are just an integer multiple of the elementary charge. q-ne where q is the net charge and n is an integer. For example, sodium can be a +1 ion and chlorine can be a -1 ion. What does this mean concerning their charge and structure? Revised 1/20 L2 D Ctlo But, what if you want to look at larger objects that are charged; e.g., objects made up of a huge number of atoms/molecules. How do these objects become charged?

Consider an electron that is 1.10-10 m from an alpha particle with charge 3.2.10-¹⁹ C. (a) What is the electric field due to the alpha particle at the location of the electron? The direction of the electric field by the alpha particle at the electron is Ela ate C (b) What is the electric field due to the electron at the location of the alpha particle? The direction of the electric field by the electron at the location of the alpha particle is #J N C |Ele- at a (c) What is the magnitude of the electric force on the electron? ✔N F = = (d) What is the magnitude of the electric force on the alpha particle? Fa= N (e) Do the two forces obey Newton's Laws?

Considering electron and proton as two charged particles separated by d = 4.5 x 10m calculate the gravitational force between the proton and electron and find its ratio to the Coulomb force. Take the mass of the proton 1.7 x 10-27 kg, the mass of the electron 9.1 x 10-³1 kg, the value of 1 the universal gravitational constant 6.7 × 10-¹1 N kg-2m-2, the electron charge -1.6 × 10- C and = 9 x 10⁹ m/F. Give the answer for Απερ the gravitational force in 10-47 N. 19

Use the following constants if necessary. Coulomb constant, k = 8.987 x 10° N m2 /C. Vacuum permitivity, eo = 8.854 x 10 12 F/m. Magnitude of the Charge of one electron, e =-1.60217662 x 10-19 C. Mass of one electron, m, = 9.10938356 x 10-31 kg. Unless specified otherwise, each symbol carries their usual meaning. For example, uC means micro coulomb. Y R. Suppose you have 5 point charges q to q, distributed along a semi-circle maintaining equal distance. The charge q6 is on the center of the circle which is also the origin of given coordinate system. The radius of the semi-circle is R = 34 cm and the magnitude of the charges are as follows : 91 = = 19 µC, q2 = q4 = 32 µC and q = q6 = -25 µC. a) Find the vector that points from q to g6 and call it F1,6- b) Calculate the coulomb force on g6 due to q in unit vector notation and call it F16 c) Find the vector that points from q3 to g6 and call it F3,6- d) Calculate the coulomb force on q6 due to g in unit vector notation and call it F36. e)…

Coulomb’s law tells us that the electrostatic force between two charged objects can be calculated by: ?= ??1?2/?^2Where k is a constant with a value of 8.99x109 Nm2/C2; ?1 and ?2 are the charges of the two particles (1.602x10-19 C), and r is the distance between the two particles. The force is attractive if the charges of the two particles is opposite (one’s positive and one’s negative) and repulsive if the charges have the same charge (both positive or both negative). Calculate the electrostatic force on proton #1 from the other two protons.Will the gravitational force between the protons be attractive or repulsive? What about the electrostatic force? Which has the larger magnitude, the electrostatic force or the gravitational force? Can the electrostatic and gravitational forces alone create a stable Lithium nucleus?

Two parallel plates are separated ?=0.00375 mx=0.00375 m and have a potential difference of ?=1610 V.V=1610 V. A small ball with mass ?=9.10×10−12 kgm=9.10×10−12 kg is placed between the two plates and remains motionless and floating between the plates. From the overall charge on the ball, determine the number of electrons ?ene the ball has gained or lost. The acceleration due to gravity is ?=9.81 m/s2,g=9.81 m/s2, and the elementary unit of charge is ?=1.60×10−19 C.