FIG. 14.1 E₁ +Vi - w R₁ = 1.2 ΚΩ - - V2 + W 13 R₂ = 2.2 k 12 + + + 20 V V3 R3 E2 10 V 3.3 ΚΩ
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Using branch-current analysis, calculate the current through each branch of the network of Fig. 14.1
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- Find the voltage across the capacitors in the given circuit under dc conditions, where R₁ = 67 Q and R₂ = 17 Q. 1092 R₁ www C₁ +51 - www 50 92 R₂ 60 V The voltage across the capacitors are v₁ = 1 + 22 HH C₂ V and v25 V.Determine the differential equation governing the voltage across the current source at t20. C1 HH 1F t= 0 1 C2 L1 31H R3 R4 2A 0.50 1F 20The figure below shows a simple RC circuit with a 3.30-μF capacitor, a 4.40-M resistor, a 9.00-V emf, and a switch. What are the following exactly 9.00 s after the switch is closed? (a) the charge on the capacitor 13.7204 UC (b) the current in the resistor 0.0110522 x Your response is off by a multiple of ten. HA (c) the rate at which the capacitor is storing energy μW (d) the rate at which the battery is delivering energy μW
- /Q6 The potential at point P due to Q1 and * :Q2 is = 1x10-12C 0.5 m 0.5 m Q2 = 1x10-12C %3D 50 cm P. 0.01797 V O -0.01271 V O ov O 0.01271 V C 10For the circuit shown in figure Req is: * 140 R3 R, R: 22 Rea Ru RC RS R7 33 6 ohm 24.4 ohm 34,4 ohm 44.4 ohmProblem 2: Determine the voltages across the wo capacitors and the currents through the two inductors under dc conditions. 55 32H C1 =2pF R1 w 1000 R2 www 500 C2 HI 1μF R3 www 300 Den L2 5H R4 900
- Find the voltage across the capacitors in the given circuit under dc conditions, where R₁ = 66 and R₂ = 19 0. R₁ www C₁ +51 1092 www ww 50 92 www R₂ 60 V 3-4 C₂ The voltage across the capacitors are v₁ = 15 + HH V and v2= V.Find equivalent capacitance for the following: a) C1 AHHHH C2 C3 C4 1µF 2µF 3uF 4µF b) C5 C9 1pF C6 2µF C10 3µF C7 4uF C11 5uF C8 6uF C12 A 7uF 8uF C29 с30 С35 C36 С37 С38 HHHH A С39 C32 42µF 42µF 1µF 2uF 3µF 4uF SuF 10μF C40 C31 C33 6pF 9uF C41 C34 ZuF 10μF C42 C43 8pF 8pF B. HHHHHFor the circuit shown, fill in the ff. table with its appropriate values. Show complete solution. C2 4uF ci ZuF C4 10uF C3 6uF 600 v CAPACITANCE VOLTAGE CHARGE ENERGY C1 = 2 uF C2 = 4 uF C3 = 6 uF C4 = 10 uF CT = VT = 600 V Qt = ET =
- Draw the Direct Form I and II diagrams of the system defined by the difference equation below. 0.4y[n] - 1.2y[n - 1] + 4.8y[n – 3] = x[n] + 4x[n – 1] + 2.4x[n – 2]Problem 4 Given the circuit with input of 80HZ, • Find the turns ratio • Find Vp(sec) • Find Vo when capacitor is removed. • Find PIV rating • Find Vripple (p-p) • Find ripple factor (rf) 5:2 Use practical Si diode Rurr 100Vrms RL 3.3 k2 C 100 uF lllDetermine the capacitor voltage vc(t) for t20. Given that Vs1 = 17V, Vs2 = 11V, C = 70nF, R₁ = 14kQ, R₂ = 13kΩ, R3= 14kΩ. FIR VS2