In a QAM system (Fig. 4.19), the locally generated carrier has a frequency error Awo and a phase error 8; that is, the receiver carrier is cos [(c + Aw)t + 8] or sin [(@c+ Aw)t +8]. Show that the output of the upper receiver branch is m₁ (1) cos [(Aw)t +8] − m₂ (t) sin [(Aw)t +8] instead of my (1), and the output of the lower receiver branch is instead of m2 (1). m₁ (1) sin [(Aw)t +8] + m₂(1) cos [(Aw)t +8] Po(t)= m(t) cos(@t)+ m₂ sin(@t) xj (1) Low-pass filter 2 cos[(@+ Aw)t +5] m/2 2 sin [(@+ Aw)t +8] Low-pass filter X₂(1) m (1) m₂(1)

In a QAM system (Fig. 4.19), the locally generated carrier has a frequency error Awo and a phase error 8; that is, the receiver carrier is cos [(c + Aw)t + 8] or sin [(@c+ Aw)t +8]. Show that the output of the upper receiver branch is m₁ (1) cos [(Aw)t +8] − m₂ (t) sin [(Aw)t +8] instead of my (1), and the output of the lower receiver branch is instead of m2 (1). m₁ (1) sin [(Aw)t +8] + m₂(1) cos [(Aw)t +8] Po(t)= m(t) cos(@t)+ m₂ sin(@t) xj (1) Low-pass filter 2 cos[(@+ Aw)t +5] m/2 2 sin [(@+ Aw)t +8] Low-pass filter X₂(1) m (1) m₂(1)

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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