f WAA = 1, WAB = 1, and WBB = 0.9, then the B allele is which of the following %3D %3D Deleterious and recessive Deleterious and dominant Additive and dominant Beneficial and recessive Dverdominant
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- Pea plants have pods that are smooth (inflated) or constricted in shape and green or yellow incolor. These two autosomal traits observe the laws of Mendelian inheritance and assortindependently of one another. One gene affects pod shape and one gene affects pod color. Theallele for the smooth shape of pods (I) is dominant over the allele for the constricted shape ofpods (i) and the allele for the green color of pods (G) is dominant over the allele for the yellowcolor of pods (g).A pure breeding female parental pea plant with smooth green pods is cross-fertilized with a purebreeding parental male pea plant with constricted yellow pods. The resulting F1 generationplants are then self-fertilized and F2 generation progeny are obtained.The distribution of the appearance or phenotypes of the pods of the F2 generation plants are______.a- 100% smooth green podsb- 100% constricted yellow podsc- 50% smooth green pods, 50% constricted yellow pods, 0% smooth yellow pods, 0%constricted green podsd-…An allelic series determines coat color in rabbits: C (full color), c (chinchilla, gray color), c` (Himalayan, white with black extremities), and c (albino, all white). The C allele is dominant over all others, c is dominant over over c, and c is recessive to all other alleles. This dominance hierarchy can be summarized as C > c the table are crossed and produce the progeny shown. h Cc X c c Parents full color × albino Himalayan x albino full color x albino full color × Himalayan full color X full color Cross A B C D 50% full color, 25% Himalayan, 25% albino 75% full color, 25% albino E Match the parental genotypes to the letter corresponding to the appropriate cross listed in the table. A CC x cc VIV B Cc x Cc Offspring 50% full color, 50% albino 50% Himalayan, 50% albino 50% full color, 50% chinchilla Cc x cc C Answer Bank h с с X сс ch Cc xcc D h h с с X сс and c, c is dominant > c> c. The rabbits in EIn addition to the allelic pair determining pattern baldness in man (B,b), consider early baldness to be due to another autosomal allele (E) on a different pair of chromosomes and also dominant in males but recessive in females. The phenotype for ee may be late or nonbaldness depending on sex and the genotype for B, b alleles. Two doubly heterozygous persons marry. What is the phenotype of the male parent? What is the phenotype of the female parent? Give the phenotypic ratio expected among male children of couples such as this one. Show corresponding genotypes for each phenotype mentioned in your phenotypic ratio. Give the phenotypic ratio expected among female children of couples such as this one. Show corresponding genotypes for each phenotype mentioned in your phenotypic ratio.
- Human ABO blood type is controlled by the I locus and has three possible alleles. The alleles which code for type A blood (IA) and type B blood (1³) are codominant, while the allele for type O blood (i) is recessive. In a cross between a person with a genotype of lªi and a person with genotype I³i, what is the probability of having three offspring with type 0 blood? O 1/4 O 1/32 O 1/64 O 1/8 O 1/16Most forms of albinism are inherited in an autosomal recessive pattern. Using a Punnett square, determine the chance that a child would phenotypically express albinism if the genotypes for both parents is Aa, where "A" indicates the dominant unaffected allele and "a" indicates the recessive affected allele. O 75% chance O 50% chance O 0% chance O 100% chance O 25% chanceTrue False One heritable factors such as recessive form could mask the presence of the alternate allele which is in dominant form A Punnett square is used to predict the genotype and the phenotype of an offspring after a genetic cross. Mendel's law of dominance states that "when parents with pure and contrasting traits are crossed together, only one form of trait appears in the next generation." A homozygous individual could have a "Ee" as genotype DNA has a ribose sugar. G..pdf rer
- In man, there is gradation in eye color and resulting to 9 phenotypes. These are (in order of the number of additive alleles): light blue, medium blue, dark blue, gray, green, hazel, light brown, medium brown, dark brown. Mr. A (dark brown eyes) and Mrs. A’s (light blue eyes) daughter, marries a man whose genotype is the same as herself. What is the probability that they could have: Dark brown eyed child? Hazel-eyed? What eye color is most likely to occur and what is its probability?The allele for hitchhiker’s thumb (h) is recessive to straight thumb (H). If a man and his wife are both homozygous recessive, will any of their offspring potentially have hitchhikers thumb? What is the man’s genotype and the woman’s genotype? What is the man’s phenotype and the woman’s phenotype? What genotype(s) must the offspring have in order to have the phenotypic trait of hitchhiker’s thumb? Do a cross to determine all potential hitchhiker’s thumb genotypes and phenotypes for the offspring of this man and woman. Is it possible for any offspring of the F1 generation to have hitchhiker’s thumb?For each of the following genotypes state whether you have a homozygous or heterozygous for each trait (you may need to use 2 terms for one genotype). AaGG Rrgg TTGg
- Albinism is a recessive autosomal trait for skin pigmentation. Hemophilia is a sex-linked recessivedisorder of the blood. assign alleles to the traitsA – normal skin pigmentation X H – normal blooda – albino X h - hemophilia A double heterozygous woman marries a non-hemophilic man and heterozygous for skinpigmentation. Double heterozygous means heterozygous for both traits. Aa for skin pigmentation andX H X h for blood trait. Therefore, the genotype of the woman is AaX H X h . Non-hemophilic man is X H Y and heterozygous for skin pigmentation is Aa. The genotype,therefore, of the man is AaX H Y. What is the probability that they will have:a. a child with normal skin? _____________________b. a child with normal blood? _____________________c. an albino girl? _____________________d. A hemophilic boy? _____________________In humans, the ABO blood type is under the control of autosomalmultiple alleles. Red–green color blindness is a recessiveX-linked trait. If two parents who are both type A and have normalvision produce a son who is color-blind and type O, what isthe probability that their next child will be a female who has normalvision and is type O?Eye Color is a trait that involves a number of genes. To simplify our example, we can break down the traitinto two phenotypes: dark color and light color eyes. Dark coloration is considered dominant, or isexpressed in a heterozygous condition (when the alleles are different).Q: If you have one light eyed parent and one parent that is homozygous for dark eye color, what are thepotential eye colors of their offspring (young)? To start, what do the Parents’ alleles look like? What istheir Genotype? (Remember, you pick which letter you want to use)Light eye colored parent:Dark eye colored parent:One of the things Mendel designed was a way to provide information about how the genes are passed onfrom parent to offspring. He designed something called a Punnett Square. This square places the parents’alleles outside the box, then uses those alleles to fill in the squares.Let’s start with a reminder of what we know about the parents: Parent Phenotype(appearance) Genotype(alleles) 1 2