HELLO SIR, COULD YOUSOLVE THIS TABLE TOPICABOUT STRENGTH OFMATERIALS LABORATORY?BENDING TESTSECOND STAGEExample: Copper MaterialDistance between anchor= 100 mmL=1mh = 6.5mm, b = 25.5 mmI=bh³/12=583.6 mm*Y=h/2= 6.5/2Mass1/RF (N)R (m)02 (N/m²)01E (N/m²)(gm)(m¹)1000.981961.238 5.463 105328.947 10.926*1014.00810¹0 1.04 10³11.06*10¹02001.962300400COO5006007700880099001010005. CALCULATIONME==RWhere:M- MomentI= Area Moment of Inertia (kg/m³)=bxh (m³)12o Stress (MPA)y c Thickness-h/2 (mm)E-Young's ModulusR- Radius of Curvature (mm)If an arm is subjected to a bending moment, we can use Equation (1) to calculate(bending stress, bending amount, bend radius of the bar, modulus of elasticity ofthe bar material). By knowing the magnitude of the effective moment (M) and themoment of inertia of the rod section (I), and in the given case in the experiment.the radius of the rod curve (R) can be calculated with an acceptable approximationaccording to the following figure:R.R-8L/2From the above triangle and according to Pythagoras law:R =- (2)² + (R-SF...................2-2x8xR+8².................. 31²R² =4While 8 is a small number, then; we can neglect (82) from other side and theequation will be come:L²2xRx8=4R=L²8x8Now as we can calculate (I, M, R) then we can also calculate Young's Modulus forthe material.By return to Equation (1) we find that:ExyRMxyIσ. =.7The value of (6) resulting from the two equations (6 and 7) proves the validity ofthe equation (1).No.123456Moment 8(N.m) (mm)0.09810.130.380.19620.530.71.071.291.491.71.892.16

Given data: Distance between the anchor = 0.1 m L= 1m h=6.5 mm b= 25.5 mm I=583.6 mm4. Y=3.25 mm

Example: Copper Material Distance between anchor= 100 mm L = Im h = 6.5mm, b = 25.5 mm I bh³/12=583.6 mm Y=h/2-6.5/2 Mass Moment 8 (gm) F (N) (N.m) 100 0.981 0.0981 200 1.962 0.1962 300 400 500 600 700 800 900 1000 No. 1 2 3 4 5 6 7 8 9 10 (mm) 0.13 0.38 0.53 0.7 1.07 1.29 1.49 1.7 1.89 2.16 R (m) 02 (N/m²) 01 5.463 10 328.947 10.926 10 961.238 E (N/m²) 14.008 10¹0 11.06 1010 1/R (m¹) 1.04 10

Example: Copper Material Distance between anchor= 100 mm L = Im h = 6.5mm, b = 25.5 mm I bh³/12=583.6 mm Y=h/2-6.5/2 Mass Moment 8 (gm) F (N) (N.m) 100 0.981 0.0981 200 1.962 0.1962 300 400 500 600 700 800 900 1000 No. 1 2 3 4 5 6 7 8 9 10 (mm) 0.13 0.38 0.53 0.7 1.07 1.29 1.49 1.7 1.89 2.16 R (m) 02 (N/m²) 01 5.463 10 328.947 10.926 10 961.238 E (N/m²) 14.008 10¹0 11.06 1010 1/R (m¹) 1.04 10

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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