Example:20 kN/mдв4m21kE = 2 *10³ kN/m²I = 1 *10-4 m4Required: AB Q AD2сAnswers in structures lectures: AB,v = 3.66 mmidETABS's Answers :AB,v = 3.681 mmI3m10KN(3) Oc; Ad,v = 0.33 mm; Adv = 0.31 mm↑; 0,= 0.00161 rad; 0,= 0.001608 rad

Answered: Image /qna-images/answer/4f7341cb-58fc-4e23-829a-950b5d1cb91e.jpg

Example: A k E = 2*10³ kN/m² I = 1 *10-4 m4 20 kN/m 4m Required: AB Ο 21 * 2m C * QAD nswers in structures lectures: Ag, 3.66 mm ↓ ETABS's Answers: Asy-3.681 mm H 3m 3 Oc ↑:00- ; Adv - 0.33 mm ; 0, -0.00161 rad ; Ady-0.31 mm; 0,-0.001608 rad

Example: A k E = 210³ kN/m² I = 1 10-4 m4 20 kN/m 4m Required: AB Ο 21 * 2m C * QAD nswers in structures lectures: Ag, 3.66 mm ↓ ETABS's Answers: Asy-3.681 mm H 3m 3 Oc ↑:00- ; Adv - 0.33 mm ; 0, -0.00161 rad ; Ady-0.31 mm; 0,-0.001608 rad

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Connections

In steel structures, connections are the members that join two or more steel members. The connections are the most important members of any steel structure, and hence, they are designed more carefully. The majority of the construction cost of steel structures is incurred due to the connections. The design of connections is done as per the recommendations and specifications of the American Institute of Steel Construction (AISC).

Question

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Example:
20 kN/m
дв
4m
21
k
E = 2 *10³ kN/m²
I = 1 *10-4 m4
Required: AB Q AD
2
с
Answers in structures lectures: AB,v = 3.66 mm
id
ETABS's Answers :
AB,v = 3.681 mm
I
3m
10KN
(3) Oc
; Ad,v = 0.33 mm
; Adv = 0.31 mm
↑
; 0,= 0.00161 rad
; 0,= 0.001608 rad

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