EXAMPLE 2.6 Determination of Aggregate Requirement for a Roadway Aggregates from a gravel pit are required for constructing a road embankment. The porosity of the aggregates at the gravel pit is 60%. The desired porosity of the compacted aggregates in the embank- ment is 25%. For a section of the embankment 7.5m wide x 0.6m compacted thickness x 1 km long, (a) calculate the volume of aggregates required. (b) Just before the construction of the embank- ment, a re-check of the porosity of the aggregates at the gravel pit was conducted. The porosity was 65% rather than 60% (an error of +8.3%), what extra percentage of aggregates would be required to construct the embankment. Assume a swell factor of 1.

EXAMPLE 2.6 Determination of Aggregate Requirement for a Roadway Aggregates from a gravel pit are required for constructing a road embankment. The porosity of the aggregates at the gravel pit is 60%. The desired porosity of the compacted aggregates in the embank- ment is 25%. For a section of the embankment 7.5m wide x 0.6m compacted thickness x 1 km long, (a) calculate the volume of aggregates required. (b) Just before the construction of the embank- ment, a re-check of the porosity of the aggregates at the gravel pit was conducted. The porosity was 65% rather than 60% (an error of +8.3%), what extra percentage of aggregates would be required to construct the embankment. Assume a swell factor of 1.

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter3: Weight-volume Relationships And Plasticity

Section: Chapter Questions

Problem 3.1P

See similar textbooks

Similar questions

1. Calculate the following properties for the data provided in the Table below for a coarse aggregate sample. a. Bulk SSD specific gravity b. Bulk Dry specific gravity A Bulk Dry Sp. Gr. = c. Apparent specific gravity d. Absorption capacity. В — С B Bulk SSD Sp. Gr. = В — С where A Apparent Sp. Gr. = А — С A = dry weight B = SSD weight C = submerged weight В — А (100) A Absorption (%) Weight of Pan + Oven- Dry Aggregate Weight of Pan Weight of Submerged Aggregate Weight of Pan + SD Aggregate 0.8495 Ib 1.9885 lb 0.6870 lb 1.9630 Ib 2. If the Moisture Content of a stockpile sample of the same coarse aggregates is 1.85 %, what is the moisture state of aggregate sample? Select from the four standard moisture states. Explain how you arrived at the answer. 3. If Bulk unit weight of coarse aggerates is 98 Ib/ft³determine the % Voids of dry-rodded aggregate. Youlk S.G(Bulk Dry)*Pwater %Solids * 100 4. Determine the % solids for 2 cases discussed in pre-lab video by using below data.…
Given a compacted aggregates with a size of 2", given the mass of aggregate plus measure equivalent to 10500g, mass of the measure is 350g and the factor of the measure is equivalent to 290 /cu. m. Calculate the Bulk density of the Sample? a. 35000 kg/m^3 b. 2903.5 kg/m^3 c. 2943.5 kg/m^3 d. 3270.07 kg/m^3
A saturated aggregate sample with an absolute volume of 5.05x10^-5 m^3 has a mass of 178 g before drying and 139 g after drying in an oven. Assume the water absorption by volume to be 59.18%. Determine the following: a. Specific gravity of the solid particles b. Mass specific gravity c. Void Ratio d. Porosity
Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained: Volume of bucket = ½ ft³ Weight of empty bucket = 20.3 lb Weight of bucket filled with dry rodded coarse aggregate Trial 1 = 69.6 lb Trial 2 = 68.2 lb Trial 3 = 71.6 lb a. Calculate the average dry-rodded unit weight b. If the bulk dry specific gravity of the aggregate is 2.620, calculate the per- cent voids between aggregate particles for each trial.
11. The lower the surface area, the lower the propensity for soil particles to stick together in a coherent mass, or as discrete aggregates. O True O False
Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained:Volume of bucket = 12 ft3Weight of empty bucket = 20.3 lbWeight of bucket filled with dry rodded coarse aggregate:Trial 1 = 76.6 lbTrial 2 = 75.1 lb Trial 3 = 78.8 lba. Calculate the average dry-rodded unit weightb. If the bulk dry specific gravity of the aggregate is 2.620, calculate the percent voids between aggregate particles for each trial.
A soil is made up of identical spherical aggregates of bulk density P= 1.3 g/cm3 whose solid phase has a particle density of pm= 2.65 g/cm3. The aggregates are packed into an arrangement with an interaggregate porosity of 0.4. Calculate the bulk density of the soil, the aggregate porosity, and the total porosity of the soil. What is the wet bulk density of the soil if the aggregates are water saturated and the interaggregate space is filled with air?
In consolidation test, we can find the (Cc, Cr, oc) from pressure - void ratio curve O Ture Fulse
: 4.34 kg Weight of cement Weight of Fine aggregate kg 8.68 : 17.36 kg M20carede Weight of coarse aggregate Weight of Water 2.36 L. Slump Test Results Group No Diagram of your slump N/mm? Mix Strength 20 mm Slump 25 Type of Slump
Calculate the void content, and the bulk density in ssd condition based on the given data. Show complete process.
Question 6.4 a) A core sample with a diameter of 1.2 in and a length of 1.8 in is saturated with brine solution of 0.26 Q.m resistivity. The resistance of the core when fully saturated with brine is measured to be 1549.3 Q. Calculate the formation factor F for this core. b) Assuming a = 1 and ø exponent m for this core? 17.6%, what is the value of the cementation %3D
The objective of the consolidation step is to achieve maximum particle packing and uniformity, so that minimum shrinkage and retained porosity will result during densification. Uniform particle size does not produce good packing. Adding particles of a size equivalent to the smallest voids reduces the pore volume to how much? O a. 23% O b. 52% О с. O d. 12% 40%