Examine the reaction mechanism found below: Step 1: HCI+S2 +Br2 HS2BrCl + Br Step 2: HCl + H S₂BrCl+Br → 2HSCI + Br2 Step 3: 2HCl + 2HSCI → 2H₂S + 2Cl2 (slow) (fast) (fast) a. Draw a circle around any reaction intermediates. b. Draw a box around any species that can be considered a catalyst. c. In the box below, provide the overall equation for this process. Overall Equation:

Examine the reaction mechanism found below: Step 1: HCI+S2 +Br2 HS2BrCl + Br Step 2: HCl + H S₂BrCl+Br → 2HSCI + Br2 Step 3: 2HCl + 2HSCI → 2H₂S + 2Cl2 (slow) (fast) (fast) a. Draw a circle around any reaction intermediates. b. Draw a box around any species that can be considered a catalyst. c. In the box below, provide the overall equation for this process. Overall Equation:

Introductory Chemistry For Today

8th Edition

ISBN:9781285644561

Author:Seager

Publisher:Seager

Chapter8: Reaction Rates And Equilibrium

Section: Chapter Questions

Problem 8.64E

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