A newsgroup is interested in constructing a 99% confidence interval for the difference in the proportions ofTexans and New Yorkers who favor a new Green initiative. Of the 548 randomly selected Texans surveyed, 384were in favor of the initiative and of the 560 randomly selected New Yorkers surveyed, 463 were in favor ofthe initiative.a. With 99% confidence the difference in the proportions of Texans and New Yorkers who favor a new Greeninitiative is between(round to 3 decimal places) and(round to 3 decimal places).b. If many groups of 548 randomly selected Texans and 560 randomly selected New Yorkers were surveyed,then a different confidence interval would be produced from each group. Aboutpercent of theseconfidence intervals will contain the true population proportion of the difference in the proportions of Texansand New Yorkers who favor a new Green initiative and aboutpercent will not contain the truepopulation difference in proportions.Question Help: Message instructorSubmit Question

The question is about confidence interval.Given :Randomly selected no. of people from state "T ( n1…

Answered: ewsgroup cting dence interval for the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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a survey is conducted to compare the proportions of men and women whoaccess their bank statements online. Denoting the population propotions by Pm and Pw, a two-proportion z-test is carried out to test Ho: pm = pw against Ha: pm > pw. The values of the test statistic is found to be z = 0.784, and the p-value for the test is found to be 0.216. Which of the following is the correct interpretation of the p-value? a) given that ha is true, the probability of getting a value of z at least as large as 0.784 is 0.216. b) given that ho is true, the probability of getting a value of z at least as large as 0.784 is 0.216. c) given the results of the survey, the probability that Pm > Pw is 0.216. d) given the results of the survey, the probability that Pm = Pw is 0.216. e) none of the above
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A polling company conducted a hypothesis test to see if people are happy with the government, and they did so by conducting a two-sided test for a population ratio. population proportion). They calculated the value of the test statistic and found that it wasz=2.1 .What is the p-value of the test?
Statistics Question
In 1995, it was determined that 78% of US citizens supported a ban on household aerosols. Thinking that this proportion may have changed over the past few decades, a sample will be taken to test if a change has occurred. In a SRS of 400 citizens taken this year, 332 supported the ban. Determine the value of the appropriate test statistic to perform this test. Round to 3 decimal places.
Support for the U.S. death penalty for convicted murderers was 63% in 2014 (Gallup poll results 2018). In a recent survey of 150 randomly selected U.S. adults, 75 said they were in favor of the death penalty for those convicted of murder. Does this sample appear to come from a population with a lower proportion in favor of the death penalty? d) Say that a = 0.05, what does this mean. Explain in the context of the problem. e) What would it mean to make a type II error? Explain in the context of this problem. f) Use a 0.05 significance level to test the claim. State your conclusion AND interpret your results.
You read a newspaper article that says that 74% of households in your town participate in a recycling program. To test that statement at the 10% significance level, you randomly select 54 households in town and you find that 35 of them participate in the recycling program. Ho: P=0.74 Ha:P=/ 0.74 Find the P-value. Round your answer to 3 decimal places.
Claim: Most adults would erase all of their personal information online if they could. A software firm survey of 508 randomly selected adults showed that 55% of them would erase all of their personal information online if they could. Find the value of the test statistic. The value of the test statistic is (Round to two decimal places as needed.) --
A study found that 13% of Americans have seen or sensed the presence of an angel. A contingent doubts that the percent is really that high. It conducts its own survey. Out of 76 Americans surveyed, only two had seen or sensed the presence of an angel. As a result of the contingent's survey, would you agree with the study? What is the p-value?
A B This graph has an r of -0.5. C D
According to an expert for the automotive industry, 68% of Americans know how to drive a manual transmission vehicle. Suppose 220 Americans are sampled. (Give results accurate to at least 4 decimal places.) a. Of the 220 people sampled, 160 respond that they know how to drive a manual transmission vehicle. What is the sample statistic p? p = b. Under the assumption that the industry expert's claim that 68% of Americans know how to drive a manual transmission vehicle is valid, what is the probability that the survey in part (a) would result in a p that is at least as high as the one found? c. Under the assumption that the industry expert's claim that 68% of Americans know how to drive a manual transmission vehicle is valid, what is the probability that the survey in part (a) would result in a p that is between 66% and 71%?

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