Evaluating the integral will lead us toQxo11E=4 tE „R? Xo (x3 + R?)/2For the case where in R is extremely bigger than x0. Without other substitutions, the equation above will reduce toE = Q/( ProblemUsing the method of integration, what is the electric field of a uniformly charged thin circular plate (with radius R and total charge Q) atxo distance from its center? (Consider that the surface of the plate lies in the yz plane)SolutionA perfect approach to this is to first obtain the E-field produced by an infinitesimal charge component of the charge Q.There will be several approaches to do this, but the most familiar to us is to obtain a very small shape that could easily represent our circularplane. That shape would be a ring.So for a ring whose charge is q, we recall that the electric field it produces at distance x0 is given byE = (1/)(x0q)/(24r2)Since, the actual ring (whose charge is dq) we will be dealing with is an infinitesimal part of the circular plane, then, its infinitesimal electric fieldcontribution is expressed as= (1/)(x024We wish to obtain the complete electric field contribution from the above equation, so we integrate it from 0 to R to obtainRE = (x0/24

The electric field due to the point charge is, dE=kdqR2 The electric field acting on the string is,…

Answered: Evaluating the integral will lead us to…

Evaluating the integral will lead us to Qxo 1 1 E= 4 TE,R2 Xo (x3 + R?)²/2 For the case where in R is extremely bigger than x0. Without other substitutions, the equation above will reduce to E = Q/(

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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