I have a question for the square root of units.So I have the formula 2pi√m/kAnd m=50g and k=32,700 dynes/cm. (dynes is g x cm/sec2)So when I plug everything in and cancel units out im left with √654sec2My question is does the square root cancel out with sec2 individually so i'll still have to square root 654 or does the square root cancel out with the whole thing and im left with 654 without having to square root it. Therefore leading to 2pi(654sec). Or would it be 2pi(25.6sec)

The formula that you are using is the formula of time. T = 2pi√m/k Here, T is time period in second.…

Answered: I have a question for the square root…

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter1: Introduction And Vectors

Section: Chapter Questions

Problem 57P

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I have a question for the square root of units.

So I have the formula 2pi√m/k

And m=50g and k=32,700 dynes/cm. (dynes is g x cm/sec²)

So when I plug everything in and cancel units out im left with √654sec²

My question is does the square root cancel out with sec² individually so i'll still have to square root 654 or does the square root cancel out with the whole thing and im left with 654 without having to square root it.

Therefore leading to 2pi(654sec). Or would it be 2pi(25.6sec)

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