Evaluate the integral by applying the following theorems and the power rule appropriately. Suppose that F (x) and G(x) are antiderivatives of f(x) and g(x) respectively, and that c is a constant. Then: (a) A constant factor can be moved through an integral sign; that is, | cf (x) dæ = cF(x)+C. %3D (b) An antiderivative of a sum is the sum of the antiderivatives; that is, |[s(x) + g(x)] dv = F(x)+ G(x)+C. (c) An antiderivative of a difference is the difference of the antiderivatives; that is, /i (2) – 9(x)] dæ = F(1x) – G(æ) + C. x"+1 The power rule: x" dx + C,r + -1. r +1 NOTE: Enter the exact answer. dx = 6x5 +C 7x +

Elements Of Electromagnetics
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Evaluate the integral by applying the following theorems
and the power rule appropriately.
Suppose that F(x) and G(x) are antiderivatives of f(x) and g(x)
respectively, and that c is a constant. Then:
(a) A constant factor can be moved through an integral sign; that is,
| cf (æ) dæ = cF(x)+C.
(b) An antiderivative of a sum is the sum of the antiderivatives;
that is,
|LS(«) + g(æ)] dæ =
F(x)+G(x)+C.
(c) An antiderivative of a difference is the difference of the
antiderivatives; that is,
/s(2) – 9(2)] de = F (æ) – G(m) + C.
The
x"+1
power
rule:
x" d.x
+ C,r + -1.
r +1
NOTE: Enter the exact answer.
7x +
6x5
dx
+C
Transcribed Image Text:Evaluate the integral by applying the following theorems and the power rule appropriately. Suppose that F(x) and G(x) are antiderivatives of f(x) and g(x) respectively, and that c is a constant. Then: (a) A constant factor can be moved through an integral sign; that is, | cf (æ) dæ = cF(x)+C. (b) An antiderivative of a sum is the sum of the antiderivatives; that is, |LS(«) + g(æ)] dæ = F(x)+G(x)+C. (c) An antiderivative of a difference is the difference of the antiderivatives; that is, /s(2) – 9(2)] de = F (æ) – G(m) + C. The x"+1 power rule: x" d.x + C,r + -1. r +1 NOTE: Enter the exact answer. 7x + 6x5 dx +C
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