Evaluate 32x24 4x² + 6x + 5 First substitute u = Then 2 dx where 4x²+6x+50. 32x+24 dx 4x²+6x+5 Now integrate with respect to u to get 32x 24 So dx = 4x²+6x+5 + C du no + C
Evaluate 32x24 4x² + 6x + 5 First substitute u = Then 2 dx where 4x²+6x+50. 32x+24 dx 4x²+6x+5 Now integrate with respect to u to get 32x 24 So dx = 4x²+6x+5 + C du no + C
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter7: Exponents And Exponential Functions
Section7.1: Multiplication Properties Of Exponents
Problem 4AGP
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