Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN: 9781285741550
Author: James Stewart
Publisher: Cengage Learning
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**Problem Statement:**

Compute \(\frac{d^2}{dx^2} \left( -x^4 - 3x^2 - x \right)\).

**Context:**

The task is to find the second derivative of the polynomial function \(-x^4 - 3x^2 - x\) with respect to \(x\). This involves differentiating the given function twice to determine how the rate of change itself changes with \(x\).

**No Graphs or Diagrams Present.**

Explanation of Solution:

1. **First Derivative** (\(f'(x)\)):
   - Start by differentiating each term of the function with respect to \(x\).
   - \(-x^4 \) differentiates to \(-4x^3\).
   - \(-3x^2 \) differentiates to \(-6x\).
   - \(-x\) differentiates to \(-1\).
2. **Second Derivative** (\(f''(x)\)):
   - Differentiate each term of the first derivative.
   - \(-4x^3\) differentiates to \(-12x^2\).
   - \(-6x\) differentiates to \(-6\).
   - The derivative of \(-1\) is \(0\).

Thus, the second derivative of the function is \(f''(x) = -12x^2 - 6\).
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Transcribed Image Text:**Problem Statement:** Compute \(\frac{d^2}{dx^2} \left( -x^4 - 3x^2 - x \right)\). **Context:** The task is to find the second derivative of the polynomial function \(-x^4 - 3x^2 - x\) with respect to \(x\). This involves differentiating the given function twice to determine how the rate of change itself changes with \(x\). **No Graphs or Diagrams Present.** Explanation of Solution: 1. **First Derivative** (\(f'(x)\)): - Start by differentiating each term of the function with respect to \(x\). - \(-x^4 \) differentiates to \(-4x^3\). - \(-3x^2 \) differentiates to \(-6x\). - \(-x\) differentiates to \(-1\). 2. **Second Derivative** (\(f''(x)\)): - Differentiate each term of the first derivative. - \(-4x^3\) differentiates to \(-12x^2\). - \(-6x\) differentiates to \(-6\). - The derivative of \(-1\) is \(0\). Thus, the second derivative of the function is \(f''(x) = -12x^2 - 6\).
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