Ethanal (CH3CHO) reacts with NaBH4, followed by H30* to give an alcohol product. The product of this reaction will be: O the R-enantiomer O the S-enantiomer O a racemic mixture O achiral N-CH, 1. NaBH4 2. Hзо The product of the above reaction will be: O an imine (no reaction) a tertiary amine a secondary amine O a primary amine

Give the letter for the enol form that is a tautomer of the aldehyde shown Д d OH Save for Later OH OH _OH a OH 1 до OH g e OH OH HO OH с OH OH Sul

Give the organic product formed in each of the following reactions, draw a 3-D representation for the product molecule showing the correct configuration

The formula for the danger sign pheromone for a species of ant is C7H7O. When treated with I2 NaOH, this pheromone produces iodoform and n-hexanoic acid. How is this pheromone structure?

The reduction of the reactant below is a R-SH O Thiol O Sulfide O Two Thiols O Disulfide

When an α-hydroxy amide is treated with Br2 in aqueous NaOH under Hofmann rearrangement conditions, loss of CO2 occurs and a chain-shortened aldehyde is formed. The mechanism involves the following steps: Base abstracts an acidic amide proton, yielding amide anion 1; The amide anion reacts with bromine in an α-substitution reaction to give N-bromoamide 2. Abstraction of the remaining amide proton by base gives a resonance-stabilized bromoamide anion 3; Rearrangement occurs to yield isocyanate 4; Water adds to the isocyanate to yield carbamic acid 5; Elimination of CO2 yields carbinolamine 6; Following proton transfer, expulsion of ammonia yields the final product aldehyde. Write out the mechanism and then draw the structures of bromoamide anion 3 and amide anion 1.