After a thorough derivation by Doraemon to establish an equation for cylindrical fuel rod of a nuclear reactor. Here he was able tocome up an equation of heat generated internally as shown below.96 = 9.where qG is the local rate of heat generation per unit volume at radius r, ro is the outside radius, and qo is the rate of heatgeneration per unit volume at the centre line. Calculate the temperature drop from the centre line to the surface for a 2.5 cm outerdiameter rod having k = 25 W/m K, if the rate of heat removal from the surface is 1650 kW/m2A619 °C719 °CC) 819 °C919 °CE1019 °CFNone of these

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Answered: er a thorough derivation by Doraemon to…

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)

8th Edition

ISBN:9781305387102

Author:Kreith, Frank; Manglik, Raj M.

Publisher:Kreith, Frank; Manglik, Raj M.

Chapter1: Basic Modes Of Heat Transfer

Section: Chapter Questions

Problem 1.68P

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After a thorough derivation by Doraemon to establish an equation for cylindrical fuel rod of a nuclear reactor. Here he was able to come up an equation of heat generated internally as shown below. 9G = 9. where qG is the local rate of heat generation per unit volume at radius r, ro is the outside radius, and qo is the rate of heat generation per unit volume at the centre line. Calculate the temperature drop from the centre line to the surface for a 2.5 cm outer diameter rod having k = 25 W/m K, if the rate of heat removal from the surface is 1650 kW/m² А) 619°C В 719 °C C) 819 °C D) 919 °C E 1019 °C F None of these
My buddy is starting to get hypothermic (body temperature 306 K) during an epic backcountry ski adventure. Since I'm quite warm (body temperature 310 K), I decide to get in a sleeping bag with him to try and warm him up. What heat transfer mechanism will be most responsible for heating him up? For simplicity, ignore any internal temperature differences across my body (that is, assume my skin temperature is also 310 K). Use numbers to support your answer (for human skin, you can use the following values: surface area A = 1:50 m2, emissivity = 0:970, thickness d = 0:0250 m, thermal conductivty 0:200 JmsK)
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In a cylindrical nuclear reactor fuel rod, heat is generated internally according to the equation:Qg= local heat generation rate per unit volume in r R0= external radiusQ1= heat generation rate per unit volume in the center lineDetermine the temperature drop from the centerline to the surface, considering that the rod has a diameter of 25 mm, thermal conductivity of 26 W / (mK), and has a heat removal rate from its surface of 1570 kW / (m²). Tip 1: It is not necessary to determine the value of the constant C2. Tip 2: the volumetric rate of energy generated is such that: Q1 = 4 . Qs/ D (solve from the image equation)
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