√(Vicosc + Ja Ra ) ² + (V sind + Jaxs)X= Sin!IXS (osd +IRSinglEo£o =Eo =(V cose + IRI² + (V since - IKCJX = Sin¹ =Ixs cose.Eo-IRSINHello my friend, tofind the load anglecan these be the laws?in synchronousgenerator? If the lawsare not valid by law

We need to correct the equation for calculation of load angle for synchronous generator

Eo = √ (Vicos + Ja Ra) ² + (V sind + Jaxs)" J= Sin IXS (osd + IRSingl. Eo Eo = (Vcos + IRI² + (V sind - I Kc) X = Sin¹= ४ Ixs cose. Eo IRSIN 2 Hello my friend, to find the load angle can these be the laws? in synchronous generator? If the laws are not valid by law

Eo = √ (Vicos + Ja Ra) ² + (V sind + Jaxs)" J= Sin IXS (osd + IRSingl. Eo Eo = (Vcos + IRI² + (V sind - I Kc) X = Sin¹= ४ Ixs cose. Eo IRSIN 2 Hello my friend, to find the load angle can these be the laws? in synchronous generator? If the laws are not valid by law

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter12: Power System Controls

Section: Chapter Questions

Problem 12.4P

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Question

√(Vicosc + Ja Ra ) ² + (V sind + Jaxs)
X= Sin!
IXS (osd +IRSingl
Eo
£o =
Eo =
(V cose + IRI² + (V since - IKCJ
X = Sin¹ =
Ixs cose.
Eo
-
IRSIN
Hello my friend, to
find the load angle
can these be the laws?
in synchronous
generator? If the laws
are not valid by law

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