Engineering strain of a mild steel sample is recorded as 0.100%. The true strain is 1. 0.010% 2. 3. 4. 0.055% 0.099% 0.101%
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- The results of a tensile test are shown in Table 1.5.2. The test was performed on a metal specimen with a circular cross section. The diameter was 3 8 inch and the gage length (The length over which the elongation is measured) was 2 inches. a. Use the data in Table 1.5.2 to produce a table of stress and strain values. b. Plot the stress-strain data and draw a best-fit curve. c. Compute the, modulus of elasticity from the initial slope of the curve. d. Estimate the yield stress.Compare the engineering and true secant elastic moduli for the natural rubber in Example Problem 6.2 at an engineering strain of 6.0. Assume that the deformation is all elastic.The data in Table 1.5.3 were obtained from a tensile test of a metal specimen with a rectangular cross section of 0.2011in.2 in area and a gage length (the length over which the elongation is measured) of 2.000 inches. The specimen was not loaded to failure. a. Generate a table of stress and strain values. b. Plot these values and draw a best-fit line to obtain a stress-strain curve. c. Determine the modulus of elasticity from the slope of the linear portion of the curve. d. Estimate the value of the proportional limit. e. Use the 0.2 offset method to determine the yield stress.
- Question 1 The ideal diameter of a steel tensile test specimen is 1 in 2 in 1/2 in 1/4 in Question 2 How many zones are exhibited by a typical stress- strain diagram 4 2Problem 4: A tensile test is carried out on a bar of a mild steel of diameter 2 cm. the bar yields under a load of 150 kN and breaks finally at a load of 70 kN. Estimate; 1-the tensile stress at the yield point 2-the ultimate tensile stress 3-the average stress at the breaking point, if the diameter of the fractured neck is 1 сm.Question 1 The ideal diameter of a steel tensile test specimen is O lin O 2 in O 1/2 in 1/4 in et Question 2 How many zones are exhibited by a typical stress- strain diagram O 3 O 5
- A steel 0.6 inch×1.2 inch steel 90 m long is subjected to a 45 KN tensile load along its lenght.If poison's ratio is 0.3 Find: A. The deformation along its lenght. B. The deformation along its thickness. C. The defirmation along uts width. D. The lateral strain.I5 In a tensile test experiment of carbon steel. a standard specimen (D= 0.505 in. Gauge length=2.0 in & total length 8 in) had a 0.2% offset yield strength of 80.000 psi and engineering strain of 0.010 at the yield strength point Calculate: The load (force) at this point. The instantaneous area of the specimen at this point. c. The true stress at this point. d. The true strain at this point. e. The total length of the specimen. if the load is released at this point.1. Calculate the strain at the centroid of the tension steel in single layer if the effective depth is 250 mm and the depth of neutral axis is 100 mm. answer: 0.0045 2. Calculate the strain at extreme layer of steel if fy=415 MPa and the strength reduction factor is 0.80. answer: 0.0038
- The strain gauge measurement of a steel plate indicate the principle strains are 0.003 and 0.001. What is the value of major principle stress in MPa? (E = 200 GPa, μ = 0.33)This figure shows typical stress-strain behaviour for a brass. The inset figure shows the behaviour at low strains. 500 70 Tosle strength 450 MPa 166,000 ps 60 400 300 MP 40 30 200 Yeld steg 250 MPa (,0a 200 20아 100- 20 100 10 0.20 030 040 If the cylindrical test sample is initially 14cm long with an initial radius of 2mm, estimate the true stress in MPa at the ultimate tensile stress. (Enter your answer to the nearest whole number) an esA metal sample on a tension in the test ,296MPa , a tensile true strain 0.08, and true stress 356 MPa when the strain is 0.27. Determine the strength coefficient and strain hardening exponent in the flow curve equation.
