Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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Encipher the following plaintext using the Vigenère cipher and key = ‘MONEY’: “make the
deposit by tomorrow”
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- Given the plaintext “I LOVE CRYPTO”, what is the ciphertext given that: Row Transposition Cipher algorithm with the key is 3214.arrow_forwardUse symmetric ciphers to encrypt message "“promise" and decrypt message "FOG". The representation of characters in modulo 26 is described as follows: Plaintext - a bcdefg|hijk1 mnopar stuvwx y z Ciphertext A BCD|EFG|HIJKL|M|NO|P|Q|R s T|U|VwxY|Z Value 00 01 02|03 04 05 06|07|08|09|10|11 12|13|14|15 16|17 18|19 20 21 22 23 24 25 The mathematical equations for encryption and decryption can be described as follows: Encryption Ea:i→i+kmod 26 Decryption Da : i→i-k mod 26 i represents the messages (plaintext or cipher), k represents a symmetric key. In this case k=20arrow_forwardThe ciphertext of the message " ILOVEMYUNIVERSITYVERYMUCH " after encryption by using Transposition cipher and the key = 5 4 3 2 1 will be: Choose one of the options: a. ALL OTHER CHOICES INCORRECT b. IMVTY LYEYM OURVU VNSEC EIIRH c. ALL OTHER CHOICES INCORRECTT d. LYEYM OURVU VNSEC EIIRH IMVTY e. VNSEC EIIRH IMVTY LYEYM OURVU f. OURVU EIIRH VNSEC IMVTY LYEYM g. LYEYM OURVU VNSEC IMVTY EIIRHarrow_forward
- Encipher the following plaintext using the Row Transposition cipher and key = 3 5 2 4 1: “ihave decided to give you a job offer”.arrow_forwardthere's an extra u at the end of the encryption how would I make that a periodarrow_forwardIn order to decode the following messages, you will need to determine the cipher used. All of them have been encrypted using one of the methods we saw in the cryptography lecture. The full key to that lecture is in canvas. Need to name the method used to decipher it and show steps in using that method. Do not hesitate to ask questions in the virtual office hours. 2. SI HT EG AS SE MD LU OH ST ON EB DR AH TA LL AR OF UO YO TE RU GI FT UO. EH TT XE NE CN ET NE SS IN AT EB AH PL AD NA DR OW DE TA LE RR OC RE HP IC.arrow_forward
- Write the solution in detail:A) Encrypt the following message using poly-alphabetic cipher:Plaintext: “HELLO WORLD”Key:Shift the first letter three positions to its rightShift the second letter five positions to its rightShift the third letter seven-position to its left B) Using the same key, decrypt the following text:Cipher text= “vjv xwb wd”arrow_forwardQuestion # 3 Assume that Dominique and Pricilla agreed to use an auto key cipher with initial keyvalue k1 = 11. Now Dominique wants to send Pricilla the following message“THE CLASS IS CANCELLED”. Encrypt the message before transmitting it over the Internet Remember: i need a Mathematics solution not computer program You must show all the steps of your workarrow_forwardAffine cipher is an example of? 1. Mono alphabetic cipher 2. Poly alphabetic cipher 3. Transposition cipher 4. Asymmetric cipherarrow_forward
- 45. Encrypt the message “success is not final, failure is not fatal” using a columnar transposition cipher for the given keyword “algebra” (1 6 5 4 3 7 2)..arrow_forwardhow to do this; Given an RSA public and private key of (note that not all of the private key is given):N = 3065977e = 425d = 713237 Decrypt the following message that has been encrypted using the public key above: 1559791arrow_forwardDecode the number using the given private key. Decode the number M = 15 using the private key d = 53 and n = 77. Assume you are decoding the number using the RSA cryptosystem. Note: You can use the Modular Exponentiation calculator to help with the calculation. a 63 (mod 77), decoded number = 63 b 64 (mod 77), decoded number = 64 C 65 (mod 77), decoded number = 65 d. 66 (mod 77), decoded number = 66arrow_forward
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