The message "KRUDEYZMSYIOEAAUONYRYEEFJVDZ" was encoded using a transposition cipher with column order 3, 1, 2, 4. Decode the message. Enter it in all caps, with no spaces.

provide your code link form repl.it.comThe ciphertext below was encrypted using a substitution cipher. In your favorite language (in C++ or Python) crack encrypted text below using frequency analysis    lrvmnir bpr sumvbwvr jx bpr lmiwv yjeryrkbi jx qmbm wi bpr xjvni mkd ymibrut jx irhx wi bpr riirkvr jx ymbinlmtmipw utn qmumbr dj w ipmhh but bj rhnvwdmbr bpr yjeryrkbi jx bpr qmbm mvvjudwko bj yt wkbrusurbmbwjk lmird jk xjubt trmui jx ibndt   wb wi kjb mk rmit bmiq bj rashmwk rmvp yjeryrkb mkd wbi iwokwxwvmkvr mkd ijyr ynib urymwk nkrashmwkrd bj ower m vjyshrbr rashmkmbwjk jkr cjnhd pmer bj lr fnmhwxwrd mkd wkiswurd bj invp mk rabrkb bpmb pr vjnhd urmvp bpr ibmbr jx rkhwopbrkrd ywkd vmsmlhr jx urvjokwgwko ijnkdhrii ijnkd mkd ipmsrhrii ipmsr w dj kjb drry ytirhx bpr xwkmh mnbpjuwbt lnb yt rasruwrkvr cwbp qmbm pmi hrxb kj djnlb bpmb bpr xjhhjcwko wi bpr sujsru msshwvmbwjk mkd wkbrusurbmbwjk w jxxru yt bprjuwri wk bpr pjsr bpmb bpr riirkvr jx jqwkmcmk qmumbr cwhh urymwk wkbmvb…

2. Encrypt the word SHIELD using an alphabetic Caesar shift cipher that starts with a shift of 8 (A to I) and shifts one additional space after each character is encrypted. Original A BC|DE F GHI J KLMN 0PQR STUV WXY Z Maps to I J KLMNOPQRS TUVW XYZ ABCDE FGH Write the encrypted message for the word SHIELD:

(1) Find a quote that you like. Make sure that the total number of characters is at least 50 and no more than 100.  (2) Then pick a number that is between 4 and 24 as your additive key.  (3) Create a table of correspondence of 26 alphabets in plaintext and the ciphertext.  (4) Use the table of correspondence to encode the quote you found in Part (1). Post the encrypted message:For example, here is a quote from John DeweyFailure is instructive. The person who really thinks learns quite as much from his failures as from his successes.We will use additive key 17. The table of correspondence between plaintext and ciphertext is as follows.(attached)      Thus the encrypted message isWRZ CLI VZJ ZEJ KIL TKZ MVK YVG VIJ FEN YFI VRC CPK YZE BJC VRI EJHLZK VRJ DLT YWI FDY ZJW RZC LIV JRJ WIF DYZ JJL TTV JJV J(5) Pick an encrypted message from your classmate and try to decrypt it. Remember to use the frequency table because you will not have access to the additive key. Make sure to include all…