Emissions are observed at wavelengths of 383.65 and 379.90 nm for transitions from excited states of the hydrogen atom to the n = 2 state. Determine the quantum numbers nh for these emissions.

Calculate the wavelength (in nanometers) of a photon emitted by a hydrogen atom when its electron drops from the n = 6 state to the n = 2 state.

Quantum numbers arise naturally from the mathematics used to describe the possible states of an electron in an atom. The four quantum numbers, the principal quantum number (n), the angular momentum quantum number (), the magnetic quantum number (me), and the spin quantum number (m§) have strict rules which govern the possible values. Identify all allowable combinations of quantum numbers for an electron. n = 5, l = 5, me = 1, ms = +31/12 n = 3, l = -2, me = 0, ms = -1/1 2 n = 4, l = 1, me = 2, ms = n = 2, l = 1, me = 0, ms = 0 n = 5, l = n = 3, l + 1/1/2 = 4, me = -4, ms = + 2 2, me = 0, ms = +ổ

An electron in an atom is known to be in a state with magnetic quantum number m₁ = −2. What is the smallest possible value of the principal quantum number n of the state? n = Ú X S