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- The data in Table 1.5.3 were obtained from a tensile test of a metal specimen with a rectangular cross section of 0.2011in.2 in area and a gage length (the length over which the elongation is measured) of 2.000 inches. The specimen was not loaded to failure. a. Generate a table of stress and strain values. b. Plot these values and draw a best-fit line to obtain a stress-strain curve. c. Determine the modulus of elasticity from the slope of the linear portion of the curve. d. Estimate the value of the proportional limit. e. Use the 0.2 offset method to determine the yield stress.PROBLEM 1) An aluminum bar carries the axial loads at the positions shown. If E=70GPA, compute the total deformation of the bar. Assume that the bar is suitably braced to prevent buckling. 0.4m D 10KN 0.8m 0.4m B 5KN 0.6m AL 20KN What is the deformation &pE in mm? A=800 mm² A=1,200 mm²PROBLEM 1) An aluminum bar carries the axial loads at the positions shown. If E=70GPA, compute the total deformation of the bar. Assume that the bar is suitably braced to prevent buckling. 0.4m D 10KN 6) What is the deformation &c in mm? 0.8m 0.4m B 5KN 0.6m 20KN A=800 mm? A=1,200 mm²
- An aluminum bar carries the axial loads at the positions shown. If E=70GPA, compute the total deformation of the bar. Assume that the bar is suitably braced to prevent buckling. 0.4m 10KN 0.8m 0.4m 5KN 0.6m What is the deformation 8Rc in mm? Al 20KN A=800 mm? A=1,200 mm²The shown plate is 60 mm thick and it is made of Magnesium Am1004-T61. The plate is fitted between the rigid frictionless supports as shown and at T, = 20°C it is stress free. Find the stresses in the x and y directions when the temperature increases to T, = 58°C. %3D 150 mm 150 mm Select one: O x: 0 MPa, y: 42.864 MPa Ox: 22.1 MPa, y: 44.2 MPa Ox: 0 MPa, y: 44.2 MPa Ox: 0 MPa, y: 17.8 MPa O x: 13.2 MPa, y: 44.2 MPa Ox: 0 MPa, y: 67.4 MPa 3:10 PM O G 4) ENG 1/31/2021Problem 1.5-2 A bar of length 2.0 m is made of a structural stoel having the stres-strain dingram shown in the figure. The yield stresa of the steel is 250 MPa and the slope of the initial lincar part of the stress-strain curve (modulus of elasticity) is 200 GP. The bar is loaded axially until it eklongates 6.5 mm, and then the load is removod. How does the final length of the bar compare with its orig- inal length? Hint: Ue the concepts illustrated in Fig. 1-36h) MP 300 200 100 0.002 0.004 0.006
- Q # 4: An aluminum rod is rigidly attached between a steel rod and a bronze rod as shown in Figure. Axial loads are applied at the positions indicated. The value of P is limited to 20 KN in bronze, 72 KN in aluminum and 28 KN in steel Find the area of each section that will not exceed a stress in steel of 280 MPa, in aluminum of 180 MPa, or in bronze of 200 MPa. CLO -2 Steel Aluminum Bronze 2P 4P 2.5 2.0 1.58 ksi, oy The normal stresses at a point in a steel member are ox 10 ksi. Using E -4 ksi, 29 x 103 ksi and v = 0.3, determine the normal strains at 2.31 %3D and oz this point. %3D ר- The rectongulor block, of material of€ length Land cross sectional ore 1 fitsH.W 3 Two aluminum alloy plates (2) are attached to the sides of a wooden beam (1) as a shown in Figure 3. mensions of the composite cross section are b1 = 80 mm, di : 240 mm, b2 = 10 mm, d2 The di- dz di %3D %3D 120 mm, and a= 60 mm. Deter- (2) (2) mine the maximum bending stresses produced in both the a (1) wooden beam and the aluminum plates if a bending moment M = +6,000 N-m is applied about the z axis. Assume that Ej = 12.5 GPa and E2 = 70 GPa. FIGURE 3 %3D
- calculate the strength reduction factor at the minimum strain of extreme tension steel f'c=28 mpa and fy=420 mpa1. See figure below and solve for the maximum value of torque the composite shaft can accommodate given a maximum shear stress of 8ksi in bronze and 12 ksi for the steel. Assume bronze has G = 6 × 103 ksi, and for steel, G = 12 × 103 ksi. %3| L C2" 3" Hollow Bronze Steel Core D = 3 in, d = 2 in D = 2 inSteel 1 m Aluminum T 0.75 m Determine the maximum permissible value of T subject to the following conditions: tt S 80 MPa, Tal 50 MPa, and the angle of rotation of the free end is limited to 0.1 radian. For T. Hollow Solid d= 30 mm D= 40 mm %3D steel, G = 82 GPa and for aluminum, G= 28 GPa. %3D d = 30 mm %3D