e Nernst Equation describes the relationship between the concentration difference of meating ion across a membrane and the membrane potential at equilibrium. The general form he equation is Ex = (RT / zF) × In ([X]out / [X]in), where Ex = membrane potential for ion x, R as constant, T = absolute temperature, z = valence of ion, F= Faraday's constant (charge per 1 ions), [X]out ion concentration outside, and [X]in = ion concentration inside. At room perature (18° C), and converting from natural logarithms (ln) to common logarithms (log), Nernst equation reduces to Ex = (0.058/z) × log ([X]out/ [X]in). What would the equilibrium entials be for each of the following ions at the given concentrations? NT: Use 58 in the Goldman equation for results in mV or 0.058 for results in V. (A) [K*]out = 3 mM, [K*]in = 150 mM (B) [Na Jout = 100 mM, [Na]in = 10 mM (C) [Cl]out = 110 mM, [CI]in = 4 mM

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The Nernst Equation describes the relationship between the concentration difference of
permeating ion across a membrane and the membrane potential at equilibrium. The general form
of the equation is Ex = (RT/zF) × In ([X]out/ [X]in), where Ex = membrane potential for ion x, R
= gas constant, T = absolute temperature, z = valence of ion, F = Faraday's constant (charge per
mol ions), [X]out = ion concentration outside, and [X]in = ion concentration inside. At room
temperature (18° C), and converting from natural logarithms (In) to common logarithms (log),
the Nernst equation reduces to Ex = (0.058/z) x log ([X]out / [X]in). What would the equilibrium
potentials be for each of the following ions at the given concentrations?
HINT: Use 58 in the Goldman equation for results in mV or 0.058 for results in V.
(A) [K*]out = 3 mM, [K*]in = 150 mM
(B) [Na]out = 100 mM, [Na*]in = 10 mM
(C) [CH]out = 110 mM, [CI]in = 4 mM
Transcribed Image Text:The Nernst Equation describes the relationship between the concentration difference of permeating ion across a membrane and the membrane potential at equilibrium. The general form of the equation is Ex = (RT/zF) × In ([X]out/ [X]in), where Ex = membrane potential for ion x, R = gas constant, T = absolute temperature, z = valence of ion, F = Faraday's constant (charge per mol ions), [X]out = ion concentration outside, and [X]in = ion concentration inside. At room temperature (18° C), and converting from natural logarithms (In) to common logarithms (log), the Nernst equation reduces to Ex = (0.058/z) x log ([X]out / [X]in). What would the equilibrium potentials be for each of the following ions at the given concentrations? HINT: Use 58 in the Goldman equation for results in mV or 0.058 for results in V. (A) [K*]out = 3 mM, [K*]in = 150 mM (B) [Na]out = 100 mM, [Na*]in = 10 mM (C) [CH]out = 110 mM, [CI]in = 4 mM
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