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- Bonomo Bulunmam G s/94048/quizzes/119102/take j3N 1179 20/150 } 19912 1172 20- 907 19912 20230° 1952 a)Ls yuk akımını bnlunuz (100 puan) b) Vac hal gerilimini veriniz(0 puan) c) Yukler üzerindekitoplamkompleks gücu hesaplavnez (10 puan) Kısa Sinavı G ASUS 14 f5 f6 f7 f8 f10الامتحان الشهري - المرحلة AlpQLScKSCe4fQCsUagXXGYBj-ULNLC_u1cR3rWh1upArLigrWMMaQ/formResponse Vss 24 4M X 4 Vce Vec 1 32 1M X8 A19 DO 2 23 D3 A16 2 31 4 A18 DI 3 22 D2 A15 3 30 4 A17 WE 21 CAS A12 4 29 A14 28 + A13 RAS 20 OE A7 NC 6 24-Pin Dip 19 A9 A6 27 A8 18 A8 A5 7 26 A9 A10 0.6" 25 - All AO 18 17 A7 A4 8. 19 32-Pin Dip 24 4 Vpp A1 19 164 A6 АЗ 10 23 A10 A2 10 15 4 A5 A2 0.6" 11 22 + CE A3 | 11 144 A4 Al 13 Vss A0 12 21 + D7 Ve 12 Top View DO + 13 20 - D6 DI 14 19 D5 D2 + 15 18 D4 Vss 16 17 + D3 Top View updated enable read activated package RAM can be Vec Vee 24 Vss 32 IM X 8 31 A19 4M X 4 2. A18 23 - > D3 A16 acer を 2quicklu pls!!! I WILL UPVTE
- c) Given the changed lines of code below, answer the following questions. ANALOG_COMPARE_SETUP: LDI R16,0 STS ADCSRA, R16 LDI R16, 0b0e*** *** STS ADCSRB, R16 LDI R16,0 STS ADMUX, R16 LDI R16,0b00000000 OUT ACSR, R16 RET What signals are now being compared? Determine if a comparator interrupt will occur (show work): Time (s) AINO (volts) AIN1 (volts) 0 1 4 1 5 4 2 1 4 3 1 0 4 1 4 4 0 alvil 5 6 5 5 Interrupt (y/n) n/a initial stateio2 (in ampere) due to 12 only= Oa. 0.9277621122789 Ob. -4.6388105613945 Oc. 2.3194052806973 Od. -2.3194052806973 (Note that io=i01+io2+io3, where io1 is due to V1, io2 is due to 12 and io3 is due to I1) io3 (in ampere) due to 11 only= Oa. 0.14201486798257 Ob. 1.4201486798257 Oc. 0.71007433991284 Od. -0.21302230197385 (Note that io=i01+io2+io3, where io1 is due to V1, io2 is due to 12 and io3 is due to I1) io (in ampere) = (Note that io=i01+io2+io3, where io1 is due to V1, io2 is due to 12 and io3 is due to I1) Power dissipated by R2 (in watt) =021 x + 196609&cmid=11648 purses This course EHide blocks stion 2 Find lo in the network shown. yet wered ked out of Flag estion 3 k2 6 k2 I. 12 mA 4 ΚΩ 2 kQ Select one: O a. 6 mA O b. 3 mA O c. None of them O d. 2 mA O e. 4 mA 11:47 PM d0 ENG 4/1/2021
- Find VGS and VDS for the E- MOSFET in the figure shown. The Datasheet information is listed with the circuit. ID(on) = 2 mA @ VGS = 3 V VGS(th) = 1.5 V ↑ Add file R₁ 10 ΜΩ VDD +5 V 15 R₂ 10 ΜΩ RD 1.5 ΚΩ00-trja-txc آنات الجادة: | 5/P Google ou - äazj X FAlpQLSfHjzeQhb11eBXC XVROM6WB4_k9XKrWwNjVtnLA_m-Q/formResponse نقطة واحده transfer charge from one body to another.. نقطة واحدة Electric field energy density is Saly laä :Superposition principle applied on Electric field defined as نقطة واحدی Conductor material is85[1+0.4432/1-.85(sqrt(48.2625/V))]=100 Solve for V