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- Rank the compounds in each group in order of increasing reactivity in electrophilic aromatic substitution: (a) C6H6, C6H5Cl, C6H5CHO, C6H5OCH3; (b) C6H5CH3, C6H5NH2, C6H5CH2NH2, C6H5CONH2.The double bond of an enamine (alkene + amine) is much more nucleophilic than a typical alkene double bond. Assuming that the nitrogen atom in an enamine is sp2hybridized, draw an orbital picture of an enamine, and explain why the double bond is electron-rich.Draw the organic products formed when cyclopentene is treated withfollowing reagent. [1] OsO4 + NMO; [2] NaHSO3, H2O
- (a) Draw the products (including stereoisomers) formed when 2methylhex-2-ene is treated with HBr in the presence of peroxides. (b) Draw the products (including stereoisomers) formed when (S)-2,4dimethylhex-2-ene is treated with HBr and peroxides under similar conditions.(NH4)3PO4 Pb(NO:)4 -> Pb3(PO4)4 NHẠNO3Rank the compounds in each set in order of increasing acid strength.(a) CH3CH2COOH CH3CHBrCOOH CH3CBr2COOH(b) CH3CH2CH2CHBrCOOH CH3CH2CHBrCH2COOH CH3CHBrCH2CH2COOH
- 22). What is the major product of the following reactions? (A) (B) Br 1) NaCN 2) CH3MgBr 3) H30*/H₂O (C) LOH (D) CN4-Methylpyridine reacts with benzaldehyde (C6H5CHO) in the presence of base to form A. (a) Draw a stepwise mechanism for this reaction. (b) Would you expect 2-methylpyridine or 3-methylpyridine to undergo a similar type ofcondensation reaction? Explain why or why not.NHCOCH3 CN When the above compound is treated with excess Br2, FeBr3, a compound with formula C,H,B12N2O2 is produced. Draw its structure.
- (a) Draw all products formed by treatment of each dibromide (A and B) with one equivalent of NaNH2. (b) Label pairs of diastereomers and constitutional isomers. H Br H Br CH3 CH3 Br H H Br ADraw the structures of the following derivatives :(i) Propanone oxime (ii) Semicarbazone of CH3CHOdeduce the type of each reaction below: