Draw the structure for the major organic product of each of the following reactions.

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Draw the structure for the major organic product of each of the following reactions. 

The image depicts a multi-step organic synthesis reaction starting with an alkene substrate. The reaction is outlined as follows:

1. **BH₃, THF**: The first step involves the addition of borane (BH₃) in tetrahydrofuran (THF) to the alkene. This likely forms a trialkylborane intermediate through hydroboration.

2. **H₂O₂, H₂O, NaOH**: The second step involves oxidation using hydrogen peroxide (H₂O₂) in the presence of water and sodium hydroxide (NaOH). This converts the trialkylborane into an alcohol through an anti-Markovnikov hydration process.

3. **NaH**: In the third step, sodium hydride (NaH) is used. This is a strong base that typically deprotonates alcohols to form alkoxide ions.

4. **CH₃Br**: The fourth step involves a reaction with methyl bromide (CH₃Br). The alkoxide formed in the previous step likely acts as a nucleophile, displacing the bromide ion to form an ether.

The reaction sequence summarizes a series of transformations that convert an alkene into a more complex organic molecule through hydroboration-oxidation, deprotonation, and etherification reactions.
Transcribed Image Text:The image depicts a multi-step organic synthesis reaction starting with an alkene substrate. The reaction is outlined as follows: 1. **BH₃, THF**: The first step involves the addition of borane (BH₃) in tetrahydrofuran (THF) to the alkene. This likely forms a trialkylborane intermediate through hydroboration. 2. **H₂O₂, H₂O, NaOH**: The second step involves oxidation using hydrogen peroxide (H₂O₂) in the presence of water and sodium hydroxide (NaOH). This converts the trialkylborane into an alcohol through an anti-Markovnikov hydration process. 3. **NaH**: In the third step, sodium hydride (NaH) is used. This is a strong base that typically deprotonates alcohols to form alkoxide ions. 4. **CH₃Br**: The fourth step involves a reaction with methyl bromide (CH₃Br). The alkoxide formed in the previous step likely acts as a nucleophile, displacing the bromide ion to form an ether. The reaction sequence summarizes a series of transformations that convert an alkene into a more complex organic molecule through hydroboration-oxidation, deprotonation, and etherification reactions.
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