Part 2 of 2 CH₁₂ H2SO4 + но CH3 Draw the structure of the alcohol product in the drawing area below. If there is no reaction, check the No reaction box under the drawing area. Click and drag to start drawing a structure. Draw the product formed in each reaction below. Part 1 of 2 CH₂ + H₂ Pd Draw the structure of the alkane product in the drawing area below. If there is no reaction, check the No reaction box under the drawing area. Click and drag to start drawing a structure. : G

Draw structural formulas for the alkoxide ion and the alkyl(aryl)bromide that may be used in a Williamson synthesis of the ether shown. CH3CH2CH2CH2-0-CH2CH2CH2CH3 • You do not have to consider stereochemistry. • Do not include counter-ions, e.g., Na*, I, in your answer. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. O Separate structures with + signs from the drop-down menu.

Identify the functional groups in the following molecule as pointed by arrow A and B, then C and D

Draw the structure of the product that forms when the carbonyl compound shown is treated with K₂ Cг2 О7. If no reaction occurs, draw the structure of the organic starting material (reactant). CH3(CH2), (CO)CH (CH3)2 Click and drag to start drawing a structure. : ☐

Identify the names of the following molecules.

PLEASE SHOW ALL DETAILED WORK

Part A For the reaction Br2 (1) 2 Br (g) at what temperature is the equilbrium constant equal to 3.5? t> VO ΤΙ ΑΣΦ 0 ? Your answer should not contain commas. No credit lost. Try again. Submit Previous Answers Request Answer K

Suggest to biochemistry

Using the bond dissociation energy table from Brightspace, calculate the enthalpy change of the following reaction: HO. + HBr Please enter your response. Submit Br + H₂O

Draw a curved arrow mechanism for the reaction, adding steps as necessary. Be sure to include all electrons that are necessary to the mechanism and all nonzero formal charges. о :0- 0-н .0. + Add/Remove step Click and drag to start drawing a structure.