Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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**Title: Understanding E1 Elimination Reaction**

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**Exercise: Identifying the Major Product in E1 Elimination**

**Objective:**

Draw the major product formed when the structure shown below undergoes E1 elimination in benzene with heat.

**Interactive 3D display mode:**

![Interactive 3D display mode](information icon here)

**Chemical Structure:**

The structure depicted is a cyclohexane ring with specific substituents:

- A methyl group (CH₃) on the second carbon.
- A bromine atom (Br) on the third carbon.
- Another methyl group (CH₃) on the fourth carbon.

The substituents are arranged as follows:

- The two CH₃ groups are on adjacent carbons, with one oriented above the plane (wedge) and the other below the plane (dash).
- The Br atom is also oriented below the plane (dash).

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**Instructions:**

Draw the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars. The single bond is active by default.

**Note:**

Understanding the E1 elimination process implies identifying the beta-carbon that will lose a proton and form a double bond with the alpha-carbon (the carbon attached to the leaving group, Br). The reaction conditions (benzene with heat) facilitate the formation of a carbocation intermediate, leading to the elimination of HBr and formation of a double bond.

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**End of Exercise**

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Transcribed Image Text:**Title: Understanding E1 Elimination Reaction** --- **Exercise: Identifying the Major Product in E1 Elimination** **Objective:** Draw the major product formed when the structure shown below undergoes E1 elimination in benzene with heat. **Interactive 3D display mode:** ![Interactive 3D display mode](information icon here) **Chemical Structure:** The structure depicted is a cyclohexane ring with specific substituents: - A methyl group (CH₃) on the second carbon. - A bromine atom (Br) on the third carbon. - Another methyl group (CH₃) on the fourth carbon. The substituents are arranged as follows: - The two CH₃ groups are on adjacent carbons, with one oriented above the plane (wedge) and the other below the plane (dash). - The Br atom is also oriented below the plane (dash). --- **Instructions:** Draw the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars. The single bond is active by default. **Note:** Understanding the E1 elimination process implies identifying the beta-carbon that will lose a proton and form a double bond with the alpha-carbon (the carbon attached to the leaving group, Br). The reaction conditions (benzene with heat) facilitate the formation of a carbocation intermediate, leading to the elimination of HBr and formation of a double bond. --- **End of Exercise** ---
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