Draw the least stable resonance form for the intermediate in the following electrophilic substitution reaction CEN Br2/FeBr3 • You do not have to consider stereochemistry. • Include all valence lone pairs in your answer. ° In cases where there is more than one answer, just draw one. Br CEN
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- Draw the most stable resonance form for the intermediate in the following electrophilic substitution reaction. CH3 CH3 CH3COCI/ AICI3 H₂C. You do not have to consider stereochemistry. Include all valence lone pairs in your answer. • In cases where there is more than one answer, just draw one.Draw the most stable resonance form for the intermediate in the following electrophilic substitution reaction. CH3 CH3 CH3CI / AICI3 • H3C • You do not have to consider stereochemistry. Include all valence lone pairs in your answer. In cases where there is more than one answer, just draw one.Draw the most stable resonance form for the intermediate in the following electrophilic substitution reaction. LOCH3 LOCH3 HNO3 / CH3CO₂H O₂N • You do not have to consider stereochemistry. • Include all valence lone pairs in your answer. ● In cases where there is more than one answer, just draw one.
- Draw the least stable resonance form for the intermediate in the following electrophilic substitution reaction. NO₂ C Br₂ / FeBr3 Br • You do not have to consider stereochemistry. Include all valence lone pairs in your answer. • In cases where there is more than one answer, just draw one. NO₂For each reaction in question 20, sketch a reaction coordinate energy diagram indicating the starting materials, transition states and any intermediates, if present, in the reaction. Don't worry about the absolute energy of starting materials and products but you can assume that the product is more stable than the starting materials.Consider this reaction: Br CH;OH Br-Br H3CO The mechanism proceeds through a first cationic intermediate, intermediate 1. Nucleophilic attack leads to intermediate 2, which goes on to form the final product. In cases that involve a negatively charged nucleophile, the attack of the nucleophile leads directly to the product. Br + CH3OH Br Intermediate 1 Intermediate 2 (product) In a similar fashion, draw intermediate 1 and intermediate 2 (final product) for the following reaction. OH + Br2 + HBr Br racemic mixture
- Draw the most stable resonance form for the intermediate in the following electrophilic substitution reaction. CH3O + You do not have to consider stereochemistry. • Include all valence lone pairs in your answer. • In cases where there is more than one answer, just draw one. ? [F H3PO4 CH3O OHConsider this reaction: Br CH3OH Br-Br H3CO The mechanism proceeds through a first cationic intermediate, intermediate 1. Nucleophilic attack leads to intermediate 2, which goes on to form the final product. In cases that involve a negatively charged nucleophile, the attack of the nucleophile leads directly to the product. H. Br + CH;OH Br Intermediate 2 (product) Intermediate 1 In a similar fashion, draw intermediate 1 and intermediate 2 (final product) for the following reaction. OH + Br2 + HBr Br racemic mixtureDraw the most stable resonance form for the intermediate in the following electrophilic substitution reaction. CH3 Br2 / FeBr3 • You do not have to consider stereochemistry. Include all valence lone pairs in your answer. • In cases where there is more than one answer, just draw one. OO. #[ ] در ChemDoodle CH3 Br
- Draw the most stable resonance form for the intermediate in the following electrophilic substitution reaction. OH CCI3 H2SO4 CCI3 CI- First stage in synthesis of the insecticide DDT, which is now banned in the US You do not have to consider stereochemistry. Include all valence lone pairs in your answer. • In cases where there is more than one answer, just draw one.10. Draw an energy diagram for the addition of HBr to 1-pentene. Let one curve on your diagram show the formation of 1-bromopentane product and another curve on the same diagram show the formation of 2- bromopentane product. Draw and label the positions for all reactants, intermediates, and products. Which curve has the higher-energy carbocation intermediate? Which curve has the higher-energy first transition state?Consider the given reaction in which NC−NC− is the nucleophile and CH3CNCH3CN is the solvent. The reactant molecule has a structure with solid and dashed wedge bonds. A solid wedge () is used to show the bond that is above the plane of the paper, and a dashed wedge () is used to show the bond that is behind the plane of the paper. Draw the product of the following reaction: