Draw the Free-Body Diagram (FBD)
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- Draw the Free-Body Diagram (FBD)
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- A steel beam having a span of 14 m. carries a dead load concentrated load Pp = 60 kN at its midspan. The beam is laterally supported at its span. Properties of the wide flange section. rts - 104.39 mm ho - 338.08 mm Jo -1.69 x 10^6 Cw - 4.3 x 10^12 d=356.11 mm tf = 18.03 mm tw - 11.18 mm Sx - 2343 x 103 mm rx = 155.96 mm ry - 93.98 mm Sy = 818 x 10^3 mm Zx = 2573 x 10^3 mm Zy= 1239 x 10^3 mm Fy = 345 MPa Iy = 151 x 10 mm Lp=3.98 Lb=14m Lr=12.98 Cb=1.14 Determine the safe concentrated live load that the beam could support at the center based on its design strengthE CH2- Resultant paf - Adobe Acrobat Pro Estended Fle Edit View Document Comments Forms Tools Advanced Windew Help 2/87 If the resultant of the two forces and couple M passes through point O, determine M. 150 mm 60° mm 30 M, = M-400x 0.15cos30-320x0.3 0 M = 148 Nm CCW 320 N 160 400 N mm Example : Replace the three forces acting on the bent beam by a single equivalent force R. Specify the distance x from the point O in which the line of action of R passes. 200 N 160 N ahid hamoodi •..5.15-7 The truss shown in Figure P5.15-7 is one of several roof trusses spaced 18 feet apart. Purlins are located at the joints and halfway between the joints. Sag rods are located midway between the trusses. The weight of the roofing materials is 15 psf, and the snow load is 20 psf of horizontal projection of the roof surface. Use LRFD and select a W shape of A992 steel for the purlins. Manual Table 6-2 may be used. 15'-0" 6 @ 15'-0" = 90'-0" an FIGURE P5.15-7
- 5.1.20 The truss shown in the figure con- sists of-4 bays of 'K' structure. Each bay has 2 m long horizontal and two 2 m long vertical bars. Find the tensions in rods DE and DG. D G J M B E H K F NO 2KN 2KN 2 KN Filenamepllignre5-1-truu7 Problem 5.1.20Identify all zero-force members (you do not need to solve for member forces). d e 10' 10' a h j k m 40k 50k 30k 8 @ 10'Draw ILD at RE This is one degree indeterminate beam
- Find 5 internal forces of the truss members. Estimate the value and the location of 3 external axial forces (vertical), also estimate the truss lengths. Note: Right support is hinge and left support is roller. 12ft 689.50 kifs 1263-50 kifs C ANA E F 741-5° kit G₁ I j gft | gft | gft | gft | gft | gft, oft, gft, 72 ft 12 ftA For the truss shown, find veyticat deflection bylunit lead Methed. EA 15 _atfd) Ioku for all members increase in temp is (50€) in (ad) short in (ad)is (3 Emfr4/39 SS Determine M 5' A L 4' B the forces in members CD, CJ, and DJ. -6 panels at 3'- L K L с J D L I H E L F L L G
- 6.9-2 Use A992 steel and select a structural tee shape for the top chord of the truss shown in Figure P6.9-2. This is the truss of Example 3.15. The trusses are spaced at 25 feet on centers and support W6 X 12 purlins at the joints and midway between the joints. The other pertinent data are summarized as follows: Metal deck: 2 psf Built-up roof: 5 psf Snow: 18 psf of horizontal roof projection a. Use LRFD. b. Use ASD. 46.6' 3' 3' 12' 3' 3' 2 @ -12' = 24- 2 @ 42' -12' = 24' 90 FIGURE P6.9-2Determine the kind of amount of stress in members of the truss shown by the method of joints or method of section P1 = 12KN P2 = 20KN P3 = 30KN P4 = 40KN P5 = 50KN U 2 U 5 Lo L1 L, L3 L4 L5 P P 5 P 1 P 2 P3 Span = 6 m at 1 m e ach pan el He ight of tru ss = 2 mThe cross-sectison of a simply supported plate girder is shown in figure. The loading on the grider is symmetrical. The bearing stiffeners at supports are the sole means of providing restraint against torsion. Design the bearing stiffeners at supports. with minimum moment of inertia about the center line of web palte only as the sole design criterion. The flat section available are: 250 x 25, 250 x 32, 200 x 28, and 200 x 32 mm. Draw a sketch 500 25 8 .1445 Dimensions in mm 20 +425