MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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The random variable X has a uniform distribution with values between 15 and 29.
What is the
(Round your answer to three decimal places.)
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- You may change one number in the table if needed to make it work x -2 2 4 1 P(x=x) 0.21 -0.03 0.32 0.18 Give a 2-decimal answer for each: Mean Variance Standard Deviationarrow_forwardssume that adults have IQ scores that are normally distributed with a mean of 100 and a standard deviation of 15 (as on the Wechsler test). Find the following: The Z-value that separates the bottom 18% from the others. The Z-Value for the 95 percentile. What is the IQ score that separates the bottom 18% from the others? The 95 percentile is? A. 113.725 B. -.92 C. 75.325 D. -.915 E. 1.645 F. 86.275 G. 124.675 H. .915arrow_forwardAssume that adults have IQ scores that are normally distributed with a mean of u= 100 and a standard deviation o = 15. Find the probability that a randomly selected adult has an IQ less than 118. Click to view page 1 of the table Click to view page 2 of the table The probability that a randomly selected adult has an IQ less than 118 is (Type an integer or decimal rounded to four decimal places as needed.)arrow_forward
- The mean is 146 and the standard deviation is 35. A score of 41 is how many z-scores below the mean?arrow_forwardAssume that adults have IQ scores that are normally distributed with a mean of mu equals 100 and a standard deviation sigma equals 20 . Find the probability that a randomly selected adult has an IQ less than 95 a. Find the z-score: z = nothing (round to 2 decimal places) b. Find the probability: nothing (use 4 decimal places)arrow_forwardIQ test scores are normally distributed with a mean of 100 and a standard deviation of 15. Find the x-score that corresponds to a z-score of 2.33. O A. 139.55 B. 142.35 OC. 125.95 D. 134.95 nswer. DII F11 F10 公arrow_forward
- n=16 mean number of television per household is 4 with a standard deviation of 1 television. using chebychev's theorem, detemine at least how many households have between 2 and 6 television.arrow_forwardA mean function E(Y IX = x) tells us: the probability of observing the value Y. O whether or not to reject the null hypothesis. how much data we need to collect. how the expected value of Y changes as X varies.arrow_forwardThe goal of the one-sample t-test is to: Group of answer choices describe the location of a score within a distribution compare the mean of a sample to the population mean. compare the means of two samples. compare the standard deviation of a sample to the standard deviation of the population.arrow_forward
- Lengths of pregnancies are normally distributed with a mean of 268 days and a standard deviation of 13 days. A baby is considered premature if the pregnancy length is at or below the third percentile (P3) of all pregnancy lengths. Find the length of pregnancy in days that separates the premature babies from those that are not considered premature. Round to the nearest integer.arrow_forwardRound z-score to the nearest hundredth and then find the required A values using the table. The amount of time customers spend waiting in line at a bank normally distributed, with a mean of 3.0 minutes and a standard deviation of 7.5 minute. Find the probability that the time a customer spends waiting is as follows. (A) Less than 3.5 minutes and (B) less than 1.5 minutes.arrow_forward
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