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Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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Question

Direction: Complete the program below using case switch statement and single array with Function. Copy
the source code and screen the sample output.
PROGRAMMING
//Single array - A group of consecutive memory locations of the same name and type, structures of related
data items.
//Array index always starts with zero.
// Single array with function
#include<iostream>
using namespace std;
// Function Name
int sumAll(int num[5]);
void display(int num[5]);
//Variable global declaration
int x, sum=0, choice;
int num[5];
main(){
// Save the input numbers to the memory
for(x=0; x<=4; x++)
{ cout<<(" Enter a number: ");
cin>>num[x];
}
cout<<"\nCHOICES: ";
cout<<"\n 1.The sum of all numbers ";
cout<<"\n 2. The sum of even subscripts";
cout<<"\n 3. The sum of even numbers ";
cout<<"\n 4. The product of odd subscripts ";
cout<<"\n 5. The product of odd numbers ";
cout<<"\n 6. The highest number ";
cout<<"\n 7. The lowest number ";
cout<<"\n 8. Display all numbers";

do{
cout<<("\n\nEnter your choice[1-7]: ");
cin>>choice;
switch(choice)
{ case 1:cout<< "Display the sum of all numbers";
sum= sumAll(num);
cout<<"\nThe sum is "<<sum;
break;
case 2:cout<< "Display the sum of numbers in even subscripts";
sum=0;
for(x=0; x<=4; x=x+2)
{ sum = sum +num[x]; }
cout<<"\nThe sum is "<<sum;
break;
case 3:cout<< "Display the sum of even numbers";
sum=0;
for(x=0; x<=4; x++)
{if (num[x] % 2==0)
{
sum = sum +num[x];
} // if
} //for loop
cout<<"\nThe sum is "<<sum;
break;
case 8: cout<< "\nDisplay all numbers\n";
display(num);
break;
default : cout<<"\nYou entered an Invalid Number\n\n";
} //switch
} while (choice<=8);
} // end of main
//START OF FUNCTION
int sumAll(int num[5]) //case 1 Sum all numbers
{ sum=0;
for(x=0; x<=4; x++)
{ sum = sum +num[x]; }
return sum; }
void display(int num[5]) // case 8 display all numbers
{

for(x=0; x<=4; x++)
{ cout<<num[x] << " "; }
}

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