Diagram on right for Problems 12-15: Assume a frictionless pulley. T FN 125a 351 kg 125 kg 351 kg a H= 0.200 351a 450 351(9.8) 12. Calculate the force of the friction (Fx) on the 351 kg mass. 125(9.8) EFy: N-351 (9.8)cos(45°) = 0 cos(45") = sin(45°) = 0.707 FN = µN 13. Calculate the acceleration a of the 125 kg mass. EFx: 351a = 351(9.8)sin(45°) - T-FN 125a = -125(9.8) +T

Diagram on right for Problems 12-15: Assume a frictionless pulley. T FN 125a 351 kg 125 kg 351 kg a H= 0.200 351a 450 351(9.8) 12. Calculate the force of the friction (Fx) on the 351 kg mass. 125(9.8) EFy: N-351 (9.8)cos(45°) = 0 cos(45") = sin(45°) = 0.707 FN = µN 13. Calculate the acceleration a of the 125 kg mass. EFx: 351a = 351(9.8)sin(45°) - T-FN 125a = -125(9.8) +T

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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