Problem 2In this problem, develop an algorithm to search a key in a sorted array.As shown in class, one general way to search a key in an array is to scan the array, comparing each element againstthe search key, until one element matches the key, or no match is found till the end of the array. In the latter case thealgorithm concludes that the key is not in the array.when the array is sorted, we can search in a more efficient way. Assume the array is sorted in ascending order. Theidea is, we retrieve the middle value from the array and compare it against the search key. If the middle value and thesearch key match, we’ve found it and the algorithm stops. If not so and the search key is smaller than the middlevalue, we search the 1st (left) half of the array as the key could not be in the 2nd (right) half (convince yourself!),otherwise -- the search key is larger than the middle value -- we search the 2nd half of the array as the key could notbe in the 1st half of thearray.In the half sub-array, we repeat the above steps, retrieving the middle key of the sub-array, comparing it against thesearch key. If they match, we've found it and stop. If they are not same, then go to either first half or second half ofthe subarray based on the comparison result.The search stops either when a match is found, or there is no subarray to search. In the latter case the algorithmconcludes that the key is not in the array. Following figure shows the steps of searching 38 in a sorted array.0 1 2 34 57 8 910Search 380205081216233856729197|L= 0 1 23M= 57 8H = 1038 > 23take 2nd Half02050812.162338567291971st Half2nd Half5 61234M= 8H = 10%3D38 < 72take 1st half02050812 16233856729197Discarded1st Half2nd HalfL=6M = 6230 1 234 5H = 78 910Found 38,Return 6050208121638567291974. Develop flowchart for this algorithm,The algorithm takes as input a search key and an array, output “key in ar: YES" or "key in arr: NO"Hint: use loop and two variables, one to store the starting index of the current search subarray andanother to store the end of the current search subarray. These variables are often called start, end, low,high, etc. Let's call it L and H. In each iteration we search array from index L to H. Initially L is Oand H is the last index of the original array. In each iteration of the loop, we get middle index M andmiddle value. If the search key is smaller than the middle values, search 1st half of the array by settingH to be M-1 (L does not change). If need to search 2nd half, set L to be M+1 (H does not change).If the search (sub)array is of even size, the middle index can be either the end of the 1st half or thebeginning of the 2nd half (so to be precise, the "middle" element should be called "middle-most"element).The loop should stop immediately when the key is found.What is the terminating condition of the search loop?Must use loops. You should not use recursions. (We will learn recursion later).Start your flowchart as shown in the following figure. The algorithm takes as input an array arr and asearch key keySave the flowchart as img_02.jpgstartarr[]keyImplement the algorithm using JavaScriptComplete the function problem20, and attach the onclick event to the corresponding button in htmlYour implementation should match your flowchart.

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Develop flowchart for this algorithm, The algorithm takes as input a search key and an array, output "key in arr: YES" or "key in arr: NO" Hint: use loop and two variables, one to store the starting index of the current search subarray and another to store the end of the current search subarray. These variables are often called start, end, low, high, etc. Let's call it L and H. In each iteration we search array from index L to H. Initially L is0 and H is the last index of the original array. In each iteration of the loop, we get middle index M and middle value. If the search key is smaller than the middle values, search 1st half of the array by setting

Develop flowchart for this algorithm, The algorithm takes as input a search key and an array, output "key in arr: YES" or "key in arr: NO" Hint: use loop and two variables, one to store the starting index of the current search subarray and another to store the end of the current search subarray. These variables are often called start, end, low, high, etc. Let's call it L and H. In each iteration we search array from index L to H. Initially L is0 and H is the last index of the original array. In each iteration of the loop, we get middle index M and middle value. If the search key is smaller than the middle values, search 1st half of the array by setting

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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