Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN: 9780133923605
Author: Robert L. Boylestad
Publisher: PEARSON
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Question
Determine IDQ and VGSQ for voltage divider bias configuration
for the JFET using graphical analysis. In addition to obtaining the VD, VS
and VDS.
We have the following data of the different elements of the circuit, such as:
R1 = 3.3 MΩ, R2 = 3.3 MΩ, RD = 860 Ω, RS = 2.2 kΩ and powered by one source 12 volts. The manufacturer's sheet indicates that IDSS = 12 mA and VP = −3 V. Include the transfer characteristic graph to obtain the values of the
point Q.
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- (a) = 56kΩ, R2 Given the voltage-divider bias configuration of Figure 2. Assume R₁ 8.2k, Rc = 6.8k, Rɛ = 1.5kQ, ß = 90, and Vcc=22V. Determine, the base current, IB, the collector current, Ic, the voltage between collector and emitter, VCE, the voltage at collector, Vc, he voltage at emitter, VE, and the voltage at base, VB. Vs Rs www + Zi R₁ C₁ R2 www ww +12V Rc RE www Figure 2 CE C₂ RL Zo ww Voarrow_forwardRE Question 3. VEE Consider: Re=5600 Rc=2K Q Vee-3V Vcc=5v Vi=2V₂,50hz Interpret the output of the basic circuit operations with Documentation of Result. Vcc t le onarrow_forwardExplain why in a voltage divider, the output voltage decreases for lesser values of load resistance RL while in a voltage follower, the output voltage almost remains constant.arrow_forward
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