Determine the total mass of solids removed over the entire 8-hour period, in kg.
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Determine the total mass of solids removed over the entire 8-hour period, in kg.
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- 3C Describe briefly why flow equalisation is used at wastewater treatment plants. Discuss briefly how this can be achieved using in-line and off-line equalisation basins. Use sketches where appropriate.A wastewater treatment plant is being designed for a small, growing community. Average flow to a wastewater treatment plant is 4.0 MGD (million gallons per day) with peak flow 50% greater than the average. They expect to use two mechanically-cleaned bar screens so that if one is down for maintenance or a problem there will still be screening available. Determine the minimum wetted area (in ft2) for each bar screen assuming the minimum approach velocity is 2ft/s.Question 16 During critical flow condition, which of the following is minimized? flow rate head depth O width
- A storm of 0.5 in/hr falls on a watershed with three time area blocks: (A: Area =100 ac, time to gage 1 hr, B: Area = 200 ac, time to gage = 2 hours, and C: Area - 300, and time to gage = 3 hours), Determine the discharge at the end of the third hour using the time area method: O a. None of the above O b. 200 cfs O c. 300 cfs Od. 100 cfsuck! Question 10 Discharge velocity is the same with seepage velocity if the value is in m per sec. O True O False No new data to save Last chc1) Chlorine contact tank (Wastewater Treatment) An activated sludge plant has a design flow (average daily flow) of 11 MGD. Determine dimensions of chlorine contact tank. The design parameters: use 1 tank. depth = 10 ft, rectangular tank: L = 4 W detention time = 15 min (based on maximum hourly flow, Q = 3 x average flow rate) I have an answer for this problem however im confussed on it. I posted is an image of the first step (solving for V) Where does the17.02 come from. I understand the (3)(11)(15) and (60) but where does the 17.02 come from?? Image 2 for problem 2 2) Chlorine contact tank (Wastewater Treatment) An activated sludge plant has a design flow (average daily flow) of 11 MGD. Determine dimensions of chlorine contact tank. The design parameters: use 1 tank. depth = 10 ft, rectangular tank: L = 4 W detention time = 15 min (based on maximum hourly flow, Q = 3 x average flow rate) I have an answer for this problem however im confussed on it. I posted is an image of…
- Question 1: You have been assigned to design primary clarifiers for a wastewater treatment plant. The average flow rate of the wastewater is 256000 m3/day with a BOD5 of 120 mg/L and suspended solids concentration of 300 mg/L. The goal is to remove 35% BOD5 and 60% suspended solids in primary treatment. Determine the following: 1) The diameter of the primary clarifier for a surface overflow rate of 50 m3/m2-day.2) The detention time in the primary clarifier and the mass of solids removed in kg/day.Assume a depth of 4m.CVNG2011 Engineering Hydrology Tutorial: UH and Flow Routing Question 3 (July 2019) The 1-hour unit hydrograph for the St. Joseph watershed at Acono is given in Table 3.1. (One unit is 1 cm.) Table 3.1 Time (h) 1 2 3 4 6. 7 8 Unit Hydrograph (m³/s) 1.8 30 86 42 15 5.5 1.8 A raingauge recorded a major storm within the catchment as having a depth of 4 cm in the first 2 hours and 5 cm in the second 2 hours. The abstraction rate is 0.34 cm/h and the baseflow is 50 m/s. a. Use the 1-hour unit hydrograph to develop the 2-hour unit hydrograph. b. What is the peak flow resulting from the storm? c. At what time did this peak flow occur?NEED ASAP There is a 1350 mm diameter sanitary sewer pipe with roughness coefficient of n = 0.022 and slope of 0.67%. Answer the following questions if the depth of the flow in this pipe is 659 mm: 17. How much is the capacity flow (Qc) of the proposed sanitary pipe? TIP: You may use Table No. 1 to help for calculation of the Qc. 18. How much is the velocity of the capacity flow (Vc) in the proposed sanitary pipe? 19. How much is the actual sanitary flow (Qa) of the project area? 20. How much is the velocity of the actual flow (Va) in the proposed sanitary pipe?
- In an orifice meter, coefficient of discharge is 0.58 and coefficient of vena contracta is 0.61, what is coefficient of velocity? AnswerMax average daily flow = 16 MGD Minimum depths 10’ for primary clarifier and 15’ for secondary clarifier Find: Dimensions of clarifiers (Hint: Consider service loading and detention time) Determine Volume by finding detention time (Assume 90 minutes = 0.0625 Days) 0.0625 Days = V / 16 MGD therefore, Volume = 1,000,000 Gallons = 133,681 ft^3 Primary Clarifier (10’ depth): Cross sectional area = 13,368.1 ft^2 =0.25*pi*d^2 therefore, d = 131 ft. = 135 ft.A new wastewater treatment plant upgrade for Pseudo City requires an equalızation basin to even out flow variations. The following hourly-average flows have been found to be typical of the average variation over a day. FLOWRATE (m³/min) 6.59 FLOWRATE (m³/min) HOUR HOUR 12 AM 1 PM 8.82 1 6.17 8.67 2 5.26 3 8.40 3 4.47 4 8.40 4 3.94 5 8.14 5 3.44 7.61 6 3.44 7 7.34 7 3.48 8 7.34 8 5.79 7.12 7.87 10 6.17 10 8.59 11 5.90 11 8.82 12 AM 6.59 12 noon 8.82 (a) What is average flow rate over a typical day? (b) What design volume is required for the equalization basin to provide for a uniform outflow equal to the average daily flow? Assume that an addition of 25% to the estimated volume will be provided to account for contingencies.