Determine the Norton equivalent of the circuit in Fig. 10.30 as seenfrom terminals a-b. Use the equivalent to find Loj2 5210/0° V892wwwFigure 10.30492wwwww=1Ω -j3Ωwww2/-90° AAnswer: ZNI, 985.5/-2.101° mA.10 Ω-j5 523.176 + j0.706 2. IN = 4.198/-32.68° A.

Determine the Norton equivalent of the circuit in Fig. 10.30 as seen from terminals a-b. Use the equivalent to find Io Π2 Ω 10/0° V 8 Ω 4Ω 1Ω -j3Ω τ (+) 22-90° A α b Figure 10.30 Answer: Zy = 3.176 + j0.706 Ω, Ι. 1ο = 985.5/-2.101° mA. 10 Ω -j5Ω = 4.198/-32.68° A.

Determine the Norton equivalent of the circuit in Fig. 10.30 as seen from terminals a-b. Use the equivalent to find Io Π2 Ω 10/0° V 8 Ω 4Ω 1Ω -j3Ω τ (+) 22-90° A α b Figure 10.30 Answer: Zy = 3.176 + j0.706 Ω, Ι. 1ο = 985.5/-2.101° mA. 10 Ω -j5Ω = 4.198/-32.68° A.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

Norton Theorem

In the current circuit law, the Norton theorem (also known as the Mayer-Norton theorem) is a simplification that can be applied to networks generated by a constant line of opposition, power sources, and current assets. In two network terminals, it can be switched on with a current supply and single resistor respectively.

Question

Determine the Norton equivalent of the circuit in Fig. 10.30 as seen
from terminals a-b. Use the equivalent to find Lo
j2 52
10/0° V
892
www
Figure 10.30
492
wwwww
=
1Ω -j3Ω
www
2/-90° A
Answer: ZN
I, 985.5/-2.101° mA.
10 Ω
-j5 52
3.176 + j0.706 2. IN = 4.198/-32.68° A.

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