Determine the minimum sample size required to construct a 90% confidence interval for the population mean. Assume the population standard deviation is 0.80 ounce. (b) The sample mean is 127 ounces. With a sample size of 13, a 90% level of confidence, and a population standard deviation of 0.80 ounce, does it seem possible that the population mean could be exactly 128 ounces? Explain.
Determine the minimum sample size required to construct a 90% confidence interval for the population mean. Assume the population standard deviation is 0.80 ounce. (b) The sample mean is 127 ounces. With a sample size of 13, a 90% level of confidence, and a population standard deviation of 0.80 ounce, does it seem possible that the population mean could be exactly 128 ounces? Explain.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
A paint manufacturer uses a machine to fill gallon cans with paint (1
normally distributed.
gal=128
ounces). The manufacturer wants to estimate the mean volume of paint the machine is putting in the cans within
0.4
ounce. Assume the population of volumes is (a) Determine the minimum sample size required to construct a
90%
confidence interval for the population mean. Assume the population standard deviation is
0.80
ounce.(b) The sample mean is
127
ounces. With a sample size of
13,
a
90%
level of confidence, and a population standard deviation of
0.80
ounce, does it seem possible that the population mean could be exactly
128
ounces? Explain.Click here to view page 1 of the Standard Normal Table.
Click here to view page 2 of the Standard Normal Table.
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(a) The minimum sample size required to construct a
90%
confidence interval is
nothing
cans.(Round up to the nearest whole number.)
Expert Solution
Step 1
(a)
Given :
Margin of error=E=0.4
Population standard deviation=σ=0.80
Significance level=α=0.10
The critical value is , Zα/2=Z0.10/2=1.645 ; The Excel function is , =NORMSINV(0.10/2)
Our aim is to find the sample size.
(b)
Given : n=13 , X-bar=127 , σ=0.80 , α=0.10
Our aim is to find the 90% confidence interval.
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