Determine the margin of error for a confidence interval to estimate the population proportion for the following confidence levels witha sample proportion equal to 0.38 and n = 100.a. 90%b. 95%c. 98%Click the icon to view a portion of the Cumulative Probabilities for the Standard Normal Distribution table....a. The margin of error for a confidence interval to estimate the population proportion for the 90% confidence level is .080(Round to three decimal places as needed.)b. The margin of error for a confidence interval to estimate the population proportion for the 95% confidence level is(Round to three decimal places as needed.)

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Answered: Determine the margin of error for a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Determine whether the normal distribution can be used to compare the following population proportions. n₁ = 33, n₂ = 46, 1 = 0.818,2 0.913 Step 1 of 2: Calculate the four values n₁₁, n₁ (1-1), n22, and n2 (1-2). Round your answers to three decimal places, if necessary.
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For the specified margin of error and confidence level, obtain a sample size that will ensure a margin of error of at most the one specified. margin of error=0.05;confidence level=95%

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