Determine the length of the vertical curve that will satisfy the passing sight distance requirement.

E] A simple circular horizontal curve connects the following two bearings: • N 75° W • S 85° E The station number at the point of intersection (PI) is 120+50.00, and the radius of the curve is 3000ft. (a). Calculate the degree of curve, curve length, and tangent length. (b). Determine the station numbers at PC and PT. (c). A sight obstruction is located at a distance of 10.00ft from the center of the inside lane of this curved two-lane two-way highway section, what is the available sight distance on the curve?

Two tangents of a simple curve have azimuth of 250 degrees 15' and 280 degrees 15' respectively and intersects at V at Station 10+ 314.62. It is required to shorten the curve to point C on the curve having a direction of N 84 degrees 15' W, 50.42 m. from the old PT without changing the degree of curve and the PC. a. Compute the new angle of intersection of the tangents. b. Compute the stationing of new PT. c. Compute the stationing of new vertex.