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Chemistry
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ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Question
![Determine the Ke if the K₂ = 2.89 for the reaction below at 327 °C.
2 NO2 (g)
N₂04 (g)
Recall that Kp = K (RT)An](https://content.bartleby.com/qna-images/question/706fa0bc-8b2b-46b5-9a0a-aff6b909f26f/1cd905e4-3e81-48f5-a2a5-7ab1610d32dc/gc0ofgk_thumbnail.png)
Transcribed Image Text:Determine the Ke if the K₂ = 2.89 for the reaction below at 327 °C.
2 NO2 (g)
N₂04 (g)
Recall that Kp = K (RT)An
Expert Solution
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Step 1
Given,
2 NO2(g) ⇌ N2O4(g)
Kp = 2.89
Temperature (T) = 327 °C = (327 + 273.15) K = 600.15 K
Kc = ?
R = 0.0821 L.atm/(K.mol)
The formula used here is,
Kp = Kc(RT)∆n
Where,
∆n = number of moles of gaseous product - number of moles of gaseous reactant
∆n = nproduct - nreactant
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