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Determine the K, if the Kp = 2.89 for the reaction below at 327 °C. 2 NO2 (g) N₂O4 (g) Recall that K₁= K (RT)An

Determine the K, if the Kp = 2.89 for the reaction below at 327 °C. 2 NO2 (g) N₂O4 (g) Recall that K₁= K (RT)An

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Determine the Ke if the K₂ = 2.89 for the reaction below at 327 °C. 2 NO2 (g) N₂04 (g) Recall that Kp = K (RT)An
Transcribed Image Text:Determine the Ke if the K₂ = 2.89 for the reaction below at 327 °C. 2 NO2 (g) N₂04 (g) Recall that Kp = K (RT)An
Expert Solution
Step 1

Given,

2 NO2(g) ⇌ N2O4(g)

Kp = 2.89

Temperature (T) = 327 °C  = (327 + 273.15) K = 600.15 K

Kc = ?

R = 0.0821 L.atm/(K.mol)

The formula used here is,

Kp = Kc(RT)∆n

Where,

∆n = number of moles of gaseous product - number of moles of gaseous reactant

∆n = nproduct - nreactant

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