At a particular temperature, K = 3.68 for the reactionSO2(g) + NO2(g) = SO3(g) + NO(g)Calculate the concentrations of all four gases at equilibrium when 0.574 mol of each gas is mixed in a 1.000-L flask. (In other words, the concentration of each gas is 0.574 M.)HOW DO WE GET THERE?We will define the change in the concentrations to reach equilibrium in terms of x. Let x equal the number of moles per liter of SO, and NO, consumed to reach equilibrium.SO2(g) + NO2(g) = SO3(g) + NO(g)Initial:0.5740.5740.5740.574Change:-X+x+x-xEquilibrium: 0.574-x0.574-x0.574+x0.574+xTherefore,[SO,]]NO][SO,]]NO,](0.574+æ)(0.574+æ)(0.574 – x)(0.574 – x)K = 3.68 =What is the value of x?X =

Answered: Image /qna-images/answer/e0653fdd-e26c-4047-805d-b7a8d6a54eb4.jpg

SO2(g) + NO2(g) = SO3(g) + NO(g) Initial: 0.574 0.574 0.574 0.574 Change: +x +x Equilibrium: 0.574–x 0.574-x 0.574+x 0.574+x Therefore, (SO3][NO] (SO,][NO,] (0.574+æ)(0.574+æ) (0.574 – a)(0.574 – æ) K = 3.68 = What is the value of x?

SO2(g) + NO2(g) = SO3(g) + NO(g) Initial: 0.574 0.574 0.574 0.574 Change: +x +x Equilibrium: 0.574–x 0.574-x 0.574+x 0.574+x Therefore, (SO3][NO] (SO,][NO,] (0.574+æ)(0.574+æ) (0.574 – a)(0.574 – æ) K = 3.68 = What is the value of x?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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