At a particular temperature, K = 3.68 for the reactionSO2(g) + NO2(g) = SO3(g) + NO(g)Calculate the concentrations of all four gases at equilibrium when 0.574 mol of each gas is mixed in a 1.000-L flask. (In other words, the concentration of each gas is 0.574 M.)HOW DO WE GET THERE?We will define the change in the concentrations to reach equilibrium in terms of x. Let x equal the number of moles per liter of SO, and NO, consumed to reach equilibrium.SO2(g) + NO2(g) = SO3(g) + NO(g)Initial:0.5740.5740.5740.574Change:-X+x+x-xEquilibrium: 0.574-x0.574-x0.574+x0.574+xTherefore,[SO,]]NO][SO,]]NO,](0.574+æ)(0.574+æ)(0.574 – x)(0.574 – x)K = 3.68 =What is the value of x?X =

Answered: Image /qna-images/answer/e0653fdd-e26c-4047-805d-b7a8d6a54eb4.jpg

SO2(g) + NO2(g) = SO3(g) + NO(g) Initial: 0.574 0.574 0.574 0.574 Change: +x +x Equilibrium: 0.574–x 0.574-x 0.574+x 0.574+x Therefore, (SO3][NO] (SO,][NO,] (0.574+æ)(0.574+æ) (0.574 – a)(0.574 – æ) K = 3.68 = What is the value of x?

SO2(g) + NO2(g) = SO3(g) + NO(g) Initial: 0.574 0.574 0.574 0.574 Change: +x +x Equilibrium: 0.574–x 0.574-x 0.574+x 0.574+x Therefore, (SO3][NO] (SO,][NO,] (0.574+æ)(0.574+æ) (0.574 – a)(0.574 – æ) K = 3.68 = What is the value of x?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

At a particular temperature, K = 3.68 for the reaction
SO2(g) + NO2(g) = SO3(g) + NO(g)
Calculate the concentrations of all four gases at equilibrium when 0.574 mol of each gas is mixed in a 1.000-L flask. (In other words, the concentration of each gas is 0.574 M.)
HOW DO WE GET THERE?
We will define the change in the concentrations to reach equilibrium in terms of x. Let x equal the number of moles per liter of SO, and NO, consumed to reach equilibrium.
SO2(g) + NO2(g) = SO3(g) + NO(g)
Initial:
0.574
0.574
0.574
0.574
Change:
-X
+x
+x
-x
Equilibrium: 0.574-x
0.574-x
0.574+x
0.574+x
Therefore,
[SO,]]NO]
[SO,]]NO,]
(0.574+æ)(0.574+æ)
(0.574 – x)(0.574 – x)
K = 3.68 =
What is the value of x?
X =

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