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Science
Chemistry
SO2(g) + NO2(g) = SO3(g) + NO(g) Initial: 0.574 0.574 0.574 0.574 Change: +x +x Equilibrium: 0.574–x 0.574-x 0.574+x 0.574+x Therefore, (SO3][NO] (SO,][NO,] (0.574+æ)(0.574+æ) (0.574 – a)(0.574 – æ) K = 3.68 = What is the value of x?
SO2(g) + NO2(g) = SO3(g) + NO(g) Initial: 0.574 0.574 0.574 0.574 Change: +x +x Equilibrium: 0.574–x 0.574-x 0.574+x 0.574+x Therefore, (SO3][NO] (SO,][NO,] (0.574+æ)(0.574+æ) (0.574 – a)(0.574 – æ) K = 3.68 = What is the value of x?
BUY
Chemistry
10th Edition
ISBN:
9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
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1 Chemical Foundations
2 Atoms, Molecules, And Ions
3 Stoichiometry
4 Types Of Chemical Reactions And Solution Stoichiometry
5 Gases
6 Thermochemistry
7 Atomic Structure And Periodicity
8 Bonding: General Concepts
9 Covalent Bonding: Orbitals
10 Liquids And Solids
11 Properties Of Solutions
12 Chemical Kinetics
13 Chemical Equilibrium
14 Acids And Bases
15 Acid-base Equilibria
16 Solubility And Complex Ion Equilibria
17 Spontaneity, Entropy, And Free Energy
18 Electrochemistry
19 The Nucleus: A Chemist's View
20 The Representative Elements
21 Transition Metals And Coordination Chemistry
22 Organic And Biological Molecules
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Chapter Questions
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At a particular temperature, K = 3.68 for the reaction SO2(g) + NO2(g) = SO3(g) + NO(g) Calculate the concentrations of all four gases at equilibrium when 0.574 mol of each gas is mixed in a 1.000-L flask. (In other words, the concentration of each gas is 0.574 M.) HOW DO WE GET THERE? We will define the change in the concentrations to reach equilibrium in terms of x. Let x equal the number of moles per liter of SO, and NO, consumed to reach equilibrium. SO2(g) + NO2(g) = SO3(g) + NO(g) Initial: 0.574 0.574 0.574 0.574 Change: -X +x +x -x Equilibrium: 0.574-x 0.574-x 0.574+x 0.574+x Therefore, [SO,]]NO] [SO,]]NO,] (0.574+æ)(0.574+æ) (0.574 – x)(0.574 – x) K = 3.68 = What is the value of x? X =
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