Determine the force (Newtons) of biceps brachii for each elbow positions given that the weight of the forearm & hands is 1.5kg at 0.15m from the elbow joint. Please show your solutions. Sample solution was provided for 30 degrees. Elbow AnglesHorizontal Distance of the weight of forear, (dx COG in meters)Force of Biceps Brachii(in Newtons)30odx = (sin30o)(0.15m)dxCOG = 0.075 mτ = (Fbiceps)(dx_biceps)+(FCOG)(dx_COG)τ = (Fbiceps)(0.03m)+(1.5kg)(-9.8m/s2)(0.075m)τ = equal to zero since the system is in statics0 = (Fbiceps)(0.03m)+(1.5kg)(-9.8m/s2)(0.075m)Fbiceps = 36.75N60o 90o 120o 150o Horizontaldistances of themuscle's0,03m30°0,045m60°OSm0.09m150° Ebow flexionattachment site tothe axis0.045m90°120°angles****

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Determine the force (Newtons) of biceps brachii for each elbow positions given that the weight of the forearm & hands is 1.5kg at 0.15m from the elbow joint. Please show your solutions. Sample solution was provided for 30 degrees. Elbow Angles Horizontal Distance of the weight of forear, (dx COG in meters) Force of Biceps Brachii (in Newtons)

Determine the force (Newtons) of biceps brachii for each elbow positions given that the weight of the forearm & hands is 1.5kg at 0.15m from the elbow joint. Please show your solutions. Sample solution was provided for 30 degrees. Elbow Angles Horizontal Distance of the weight of forear, (dx COG in meters) Force of Biceps Brachii (in Newtons)

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter8: Centroids And Distributed Loads

Section: Chapter Questions

Problem 8.73P

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Elbow Angles	Horizontal Distance of the weight of forear, (d_{x COG} in meters)	Force of Biceps Brachii (in Newtons)
30^o	dx = (sin30^o)(0.15m) dx_COG = 0.075 m	τ = (F_biceps)(dx_{_biceps})+(F_COG)(dx_{_COG}) τ = (F_biceps)(0.03m)+(1.5kg)(-9.8m/s2)(0.075m) τ = equal to zero since the system is in statics 0 = (F_biceps)(0.03m)+(1.5kg)(-9.8m/s²)(0.075m) Fbiceps = 36.75N
60^o
90^o
120^o
150^o