Structural Analysis
6th Edition
ISBN: 9781337630931
Author: KASSIMALI, Aslam.
Publisher: Cengage,
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Solve for all forces
Transcribed Image Text:Determine the force in each member of the truss shown in (Figure
State if the members are in tension or compression. Take that
P = 140 lb.
Figure
-2 ft-
-2 ft
B
3 ft
1 of 1
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- Shown below are 4 different rigid bodies, supported in different ways. For each of the rigid bodies, with proper free body diagrams, please determine all the support reactions. Value of the applied forces is F = 100 N, P = 200 N and L = 3 m. a. In figure a, support is a pin at A and a roller at D. Pin at A resists translation in the horizontal and vertical direction, and roller at D only resists translation in the vertical direction. b. In figure b, support at A is a pin it similar to part a of the problem), and support at D is a roller on an incline: note that here, the roller support reaction will be normal to the incline. c. In figure c, support at A is a roller, and support at D prevents translation in the horizontal direction, and also prevents rotation. So, there will be two support reactions at D. Think of what they may be? d. In figure d, support at A is a cantilevered end. B 30° (a) (b) |F | F |P (c) (d) /3arrow_forward50 kN A 200 mm B 350 mm a a 60 mm 200 mm - change the length of segment BC from 350 mm to 312 mm 50 mm 20 mm 20 mm D 20 mm 50 kN Provide the internal normal force diagram for the figure above with the following modifications:arrow_forwardPlease correct my understanding of this question. -In the equation of the moment at point A, there is a value, 36(11.5). I assume that is a force from the distributed load. -If you are finding the moment at point A, wouldn't you only need one value from the distributed load which is 27(10)? So my question is how do you get the value of 36 and 11.5, separately. And what is it for?arrow_forward
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