Determine the force in each member of the 300 N truss in Fig. Q1, and state if the members are in tension or compression. Note: That equilibrium analysis of joint A can be used to determine the components of the support reaction at A using the results obtained 400 N DV 2 m 250 N above. B. 2 m [FDc = 400N (C), FDA = 300N (C), FB 250N (T), FBc = 200N (T), FCA = 283N (C)] %3D 200 N %3D Fig. Q1

A metal rod of mass M = 6 kg and length L = 0.5 m, is attached at one end by a hinge to a vertical wall. It is initially supported at the other end so that it is in static equilibrium and lies horizontally. hinge support (a) (i) Determine the magnitude and direction of the force on the bar due to the support. (ii) Determine the magnitude and direction of the force on the bar due to the hinge. (b) Show that the moment of inertia of the bar about the end that is attached to the wall is ly = 0.5 kg m2 (c) The support is removed and the bar swings down about the end attached to the hinge. What is the acceleration of a point on the end of the rod just after the support is removed (at this instant the acceleration vector will point directly down)? Give your result in terms of g.

(a) Determine the reactions at A and E if P = 1160 N. The reactions are positive if to the right or up, negative if to the left or down. (b) What is the maximum value which P may have for static equilibrium? Neglect the weight of the structure compared with the applied loads. 3.9 m Answers: Ax= (a) If P = 1160 N, Ay= Ex= E Mi M. 4.8 m Pmax = i B 31, 4780 N y T I le D 4.8 m P N N N C (b) The maximum value which P may have for static equilibrium: N

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