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- A cable with supports at the same elevation has a span of 600 ft. The length of the cable is 630 ft. If the max- imum tension in the cable resulting from a uniformly dis- tributed load w along the horizontal is 360 kip, determine The sag in the cable at the middle of the span.Determine the weight of the heaviest cylinder which can be placed in the position shown without exceeding a stress of 50 MN/m2 in the cable BC. Neglect the weight of the bar AB. The cross – sectional area of cable BC is 100mm2.The rigid bar ABC is suspended from three wires of the same material. The cross-sectional area of the wire at B is equal to half of the cross-sectional area of the wires at A and C. Determine the tension in each wire caused by the load P.
- a b c d F 5 m 1.5 m 2.1 m 2.4 m 26 kN The structure above is subjected to a load at point C. Using the table below, determine the forces acting at the support pins and at pin B on member ABC. Forces: (Denote tension forces with positive values; compressive forces with negative values.) FAX = ? FAY = ?Determine the force in each member of the space truss given F=3 kN. Use positive to indicate tension and negative to indicate compression. FAB = 3.23 FAC = 0.75 FAD = 0.75 FBC= 1.84 FBD= 1.84 FBE = 2.41 3m E -2 m. 3 m -4 m. ✓0 kN X KN X KN X KN X KN OKN B F 5 m4. A short compression member carries eccentric load P = 650 lb situated 1.25 ft from the axis of the member. Determine the equivalent axial load and a couple that is applied at the axis of the member. P = 650 Ib
- For the reinforcement shown, determine the force to which the bars are subjected, indicating whether they are in tension or compression. 3 m A B -3 m- -3 m- 6 kN -3 m- -3 m- 5 D 8 kN -3 m 3 m 14:3 EFor the frame and loading shown, determine the components of all forces acting on member ABD. Given that P₁ = 420lb, P2 = 300lb. 6 in. -9 in.9 in.9 in.- P₁ D E 12 in. 12 in.A RIGID BAR "AB" ATTACHED TO TWO VERTICAL RODS IS HORIZONTAL BEFORE LOAD P IS APPLIED. DETERMINE THE VERTICAL MOVEMENT OF POINT CIF THE MAGNITUDE OF P IS 60 KN.
- Determine the internal resultants FG, VG, and MG on the cross-section at G of the horizontal frame member. The uniformly distributed load on member AC has a magnitude w0=220 lb/ft. (See the inset for a definition of the resultants.)Determine the components (magnitude, direction, and sense) of all forces on frame member ABC shown if it is being subjected to a load of F=18Kips. B C 10.8 ft 18 Kips 6 ft + D 6 ft E F + VI of llor S 6 f4. Determine the axial forces for every member of the truss ( 201N B 60 3m 40kN 3m Sur 3m G 2.6 10kN