Determine the electric field strength in volts per meter between the points indicated below. Given Values: • VA=3.50V ° ° VB=6.20V VC=8.80V • Distances: ° ° The distance between A and B is 2.0 cm. The distance between B and C is 3.5 cm. Calculate the electric field strength between: • A and B • B and C Between which two points is the electric field the strongest?

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The force between two electrons in a vacuum is 1x10^-15N. How far apart are the electrons? * 1.2x10^(-7) m B. 2.4x10^(-7) m OC. 3.6x10^(-7) m O D. 4.8x [10) ^(-7) m O O O O

9:46 & M A • 4_591137447545825... ad cz1 c Jouandna id cuo m Iu:Ciouna A of charge on its plates, what is the unknown capacitance? 24. Three concentric, thin conducting cylindrical shells have radii of 0.2, 0.5, and 0.8 cm. The space between the shells is filled with air. The innermost and outermost cylinders are connected at one end by a conducting wire. Find the capacitance per unit length of this system. 25. A rectangular parallel-plate capacitor of length a and width b has a dielectric of width b partially inserted a distance x between the plates, as shown in Figure . (a) Find the capacitance as a function of x. Neglect edge effects. (b) Show that your answer gives the expected results for x = 0 and x = a 26. The two capacitors shown in Figure have capacitances C1 = 0.4 µ and C2 = 1 .2 µF. The voltages across the two capacitors are V1 and V2, respectively, and the total stored energy in the two capacitors is 1.14 mJ. If terminals band c are connected together, the voltage is 4…

High Voltage Technique The puncture strength of the insulator in a coaxial cylindrical electrode system with outer cylinder radius r2=10 cm varies from inner cylinder radius r1 [cm] to Ed=30+10/r1 [kV/cm]. a) Determine the limits of the values ​​that r1 can take in order to apply 80 kV to the system. b) Calculate the maximum field strength of the most suitable system for U=80 kV. c) For r1'=0.5 cm, r1"=3.5 cm and r1"'=8.5 cm, evaluate the system in terms of discharge events at U=80 kV. ANSWERS: a) 0.63 cm<r1<6.93 cm b) Emax=21.75 kV/cm

(1) How many electrons are contained in a -1 C of charge?  A. 5.4 × 10^15 electronsB. 5.4 × 10^18 electronsC. 6.2 × 10^15 electronsD. 6.2 × 10^18 electronsE. None of the Above (2) What is the total mass of the electrons in question 1? Me= 9.11 × 10^-31 kg A. 5.6 × 10^−12 kgB. 5.6 × 10^−15 kg C. 3.7 × 10^−12 kg D. 3.7 × 10^−15 kgE. None of the Above (3) If two equal charges, each of 1 C, were separated in air by a distance of 1 km, what would be the force between them? k = 9.0 × 10^9 Nm^2/C^2 A. 9.0 mNB. 9.0 kNC. 9.0 MND. 9.0 GNE. None of the Above (4) Two point charges, Q1 and Q2, are 3 m apart, and their combined charge is 20 µC. If one repels the other with a force of 0.075 N, what are the magnitudes of the two charges? A. 8 µC and 12 µCB. 10 µC and 10 µCC. 15 µC and 5 µCD. 18 µC and 2 µCE. None of the Above (5) From question 4, if one attracts the other with a force of 0.525 N, what are the magnitudes of the charges? Choose two answers.  A. 15 µC and -35 µCB. -15 µC and 35 µCC. 40…

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A proton (m = 1.67 x 10-27 kg) travels a distance of 3.4 cm parallel to a uniform electric field 3 x105 V/m between the plates shown in the figure. If the initial velocity is 1.9 x 105 m/s, find the magnitude of its final velocity in m/s. (* Ignore gravity) Round your answer to 0 decimal places.

E = E1 E = 0 E= E1 E= E1 The electric field is measured all over a cubical surface, and the pattern of field detected is shown in the figure above. On the right side of the cube, the electric field has magnitude Ej = 426 V/m, and the angle between the electric field and the surface of the cube is 0 = 15 degrees. On the bottom of the cube, the electric field has the same magnitude Ej, and the angle between the electric field and the surface of the cube is also 0 = 15 degrees. On the top of the cube and the left side of the cube, the electric field is zero. On half of the front and back faces, the electric field has magnitude Ej and is parallel to the face; on the other half of the front and back faces, the electric field is zero. One edge of the cube is 41 cm long. Part 1 What is the net electric flux on this cubical surface? Net electric flux = i V•m Save for Later Attempts: 0 of 4 used Submit Answer

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