Determine the concentrations of all major species in a solution of 1.06 M chronic acid, H,CrOlag). For this acid. K₁1-0.18 and K- 32x107 Your answer is partially correct HyCrOjall 101 [HC+O/loa-0179 (Cro, loal 320/7 (H₂O- pH- 07447 0.1800 M M M M
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![## Determination of Concentrations in Chromic Acid Solution
### Problem Statement
Determine the concentrations of all major species in a solution of 1.06 M chromic acid, H₂CrO₄(aq). For this acid, \( K_{a1} = 0.18 \) and \( K_{a2} = 3.2 \times 10^{-7} \).
### Solution
The concentrations of the species and the pH of the solution are determined as follows:
1. **Concentration of H₂CrO₄(aq)**: \( [H₂CrO₄] = 1.01 \) M
2. **Concentration of HCrO₄⁻(aq)**: \( [HCrO₄⁻] = 0.179 \) M
3. **Concentration of CrO₄²⁻(aq)**: \( [CrO₄²⁻] = 3.2 \times 10^{-7} \) M
4. **Concentration of H₃O⁺(aq)**: \( [H₃O⁺] = 0.1800 \) M
5. **pH of the solution**: \( \text{pH} = 0.7447 \)
### Graphs and Diagrams
There are no graphs or diagrams included in the analysis.
### Notes
- The values provided are based on precise calculations, considering the dissociation constants \( K_{a1} \) and \( K_{a2} \) for the stepwise dissociation of H₂CrO₄ in water.
- The pH value is derived from the concentration of hydronium ions (\( [H₃O⁺] \)) using the formula \( \text{pH} = -\log[H₃O⁺] \).
### Assistance
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