
Elements Of Electromagnetics
7th Edition
ISBN: 9780190698614
Author: Sadiku, Matthew N. O.
Publisher: Oxford University Press
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Determine the composition of the phases;
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- Quenching is a process used to preserve at room temperature a phase which exists in equilibrium at high temperature but which would decompose during equilibrium cooling. Explain the basis of this process in the precipitation process and martensitic transformation. Use phase diagrams when necessary.arrow_forwardDetermine C (the number of components), P (the number of phases) and F (the variance) of the system in each region of the phase diagram.arrow_forward. Which one of the following statements about a phase diagram is incorrect? (a) Solid solubility limits are depicted by it. (b) It indicates the temperature at which different phases start to melt. (c) It gives information on transformation rates. (d) Relative amount of different phases can be found under given equilibrium conditions.arrow_forward
- The question is the image, and could you explain to me how to get the answer because the teacher never discusssed this type of exercise in class and i don't know the proccess of solving itarrow_forwardAccording to the following graph, two samples of 1080 steel are cooled from the eutectoid temperature, one at a cooling rate of 250°C/s and the other at a cooling rate of 7.27x10-8 °C/s. Specify the phases obtained and explain their formation from thermodynamic and kinetic perspectives. Also, briefly describe their formation. Draw the microstructure of the phases obtained. Sıcaklık (C) 800 700 600 500 400 300 200 100 0 10 1 T M(başlama) M(% 50) M(% 90) 10 M+O -Otektoid Sıcaklık 10² Zaman (s) % 50 10³ 104 105arrow_forward37arrow_forward
- In a binary phase diagram ( pressure omitted) what is the maximum number of phases that can coexist for at least one degree of freedom?arrow_forwardConsider the phase diagram below. The three points A, B, and C are at concentrations of 27, 31.9, and 33.8 wt% Ni respectively. The ends of the tie line are at C1 = 25% wt% Ni and C2 = 35 wt% Ni. What are the weight fractions of the alpha phase at A and the L phase at B, as well as the alpha phase/L phase ratio at C? T(°C) 1300-L (liquid) 1200 20 ABC L + a C1 30 S C2 liquidus 40 L + a solidus α (solid). O a. Walpha=0.12; WL=0.41; Walpha/WL = 9.41 O b. Walpha=0.27; WL-0.26; Walpha/WL = 11.11 O c. Walpha=0.15; WL-0.26; Walpha/WL = 11.80 Od. Walpha=0.20; WL-0.31; Walpha/WL = 7.33 50 wt% Niarrow_forwardImagine a substance with the following points on the phase diagram: a triple point at .5 atm and -5ºC; a normal melting point at 20ºC; normal boiling point at 150ºC; and a critical point at 5 atm and 1000ºC. The solid liquid line is “normal” (meaning positive sloping). For this, complete the following: 1. Describe what one would see at pressures and temperatures above 5 atm and 1000ºC. 2. Describe what will happen to the substance when it begins in a vacuum at -15 ºC and is slowly pressurized. 3. Describe the phase changes from -80ºC to 500ºC at 2 atm.arrow_forward
- Could someone explain in detail how to solve this problem please. I really dont understand it. Thank you so much.arrow_forwardConsider the phase diagram below. The three points A, B, and C are at concentrations of 26.4, 31.3, and 34 wt% Ni respectively. The ends of the tie line are at C1 = 25% wt% Ni and C2 = 35 wt% Ni. What are the weight fractions of the alpha phase at A and the L phase at B, as well as the alpha phase/L phase ratio at C? T(°C) 1300 L (liquid) 1200 20 A B C L + a C1 S liquidus L + a solidus a (solid) 50 wt% Ni a. Walpha=0.21; WL=0.33; Walpha/WL = 13.17 b. Walpha=0.09; WL=0.32; Walpha/WL = 15.00 c. Walpha=0.07; WL=0.46; Walpha/WL = 11.17 d. Walpha=0.14; WL=0.37; Walpha/WL = 9.00arrow_forwardCalculate the slope of the liquid/solid phase boundary (in a temperature-pressure phase diagram) for ethanol, at T = 158.7 K. Assume the density of solid ethanol at that temperature is 0.83 g/cm3 , and that the density of liquid ethanol doesn't vary with temperature. Can someone explain this? I'm very confused.arrow_forward
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